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zvonat [6]
3 years ago
15

Jacob needs less than 5 C's on his transcript to qualify for UGA. He already has 1 C. At most, how many more C's can he get and

still be able to go to UGA? Write an inequality and solve.
Mathematics
2 answers:
victus00 [196]3 years ago
6 0
<span>C' x + 1 < 5 ; x < 4 ...............................................................................................</span>
olya-2409 [2.1K]3 years ago
5 0

Answer:

answer is C fo sho

Step-by-step explanation:

Since Jacob needs less than 5 C's the inequality is <. He already has 1 so add that to the number of remaining ones he can get. The correct answer is x + 1 < 5; x < 4 .

You might be interested in
Find the value of x when : 2^30/8^9=2^x
artcher [175]

Answer:

x = -3

Step-by-step explanation:

Okay, the first thing to do is get that 8 away from the fraction. How can we do it? When you have 2³ you have 8, is the same thing, so let's do it:

2³⁰/(2³)⁹ = 2^x

When you have a number with the shape (a^x)^y, you can write it as a^(x•y), so:

(2³)⁹ = 2^3•9 = 2²⁷

Now we have:

2³⁰/2²⁷ = 2^x

When you have a division like this: (a^x)/(a^y), you can write it as a^(x-y), so:

2^(30-27) = 2^x

2^-3 = 2^x

Now you know that x = -3

3 0
3 years ago
Can you answer these plz?
xxMikexx [17]

Answer: the answer is d

7 0
2 years ago
What is the identity of 8z^3+27
Alik [6]

8 is a cube: 2³

27 is a cube: 3³

The expression can be identified as "the sum of two cubes": (2z)³ + 3³.

8 0
3 years ago
I'm solving systems and I don't understand how to do it pls helpp
kaheart [24]

Answer:

Use the process of elimination. I'll only do one example since you have 4.

Step-by-step explanation:

Let's do the first question.

2x-3y=-11

2x+y=9

Our goal here is to be left with one variable to solve, this way we can use the answer for that variable to find the other. A.K.A only find X to plug into the equation to find Y. To do this, we'll use the process of elimination, in which we need to cancel out a variable.

X seems the easiest here. To cancel 2 (in the top equation), you need to have a -2. And that -2 needs to be the x coefficient in the 2nd equation, in order for us to "cancel" it out. To get -2, you multiply 2 by -1.

-1(2x+y)= -1(9)

Note that whatever you do to one side, you need to do it to both sides! Hence, why I also multiplied 9 by -1. You should now be left with:

-2x -y = -9

Now, we cancel out the positive 2 and -2 from both equations by adding the two equations.

2x-3y= 11

+

-2x-y=-9

X cancels out, so we're left with -4y=-20. Solve for Y, which is 5.

-4y=-20

y=5

Now that you have the Y value, plug it into any of the two equations to find your X value.

2x-3y=11

2x-3(5)=11

2x-15=11

2x=26

x=13

And voilah! Our Y value is 5, and our X value is 13.

It's pretty simple once you understand what's going on. All that we did was to cancel out one variable (either X or Y) in the two equations so that we're left with only one variable to solve. If we cancel out X, we only need to solve for Y. You do this by manipulating one of the two equations (doesn't matter which one). Once you find either X or Y, all you need to is to plug it into one of the original equations. Then, you'll have both X and Y.

And that my friend, is the process of elimination. Good luck!

8 0
2 years ago
Read 2 more answers
The amount of money Kelly earns is proportional to the number of hours she works. Kelly earns $32.40 working 4 hours. Create an
UkoKoshka [18]
She earns 32.40 for working 4 hrs.....32.40/4 = 8.10 per hr

y = 8.10h...where y is the amount of money earned and h is the number of hrs worked
4 0
3 years ago
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