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zvonat [6]
3 years ago
15

Jacob needs less than 5 C's on his transcript to qualify for UGA. He already has 1 C. At most, how many more C's can he get and

still be able to go to UGA? Write an inequality and solve.
Mathematics
2 answers:
victus00 [196]3 years ago
6 0
<span>C' x + 1 < 5 ; x < 4 ...............................................................................................</span>
olya-2409 [2.1K]3 years ago
5 0

Answer:

answer is C fo sho

Step-by-step explanation:

Since Jacob needs less than 5 C's the inequality is <. He already has 1 so add that to the number of remaining ones he can get. The correct answer is x + 1 < 5; x < 4 .

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Really need help :( struggling
Scorpion4ik [409]

Answer:

B

Step-by-step explanation:

The original amount will be the coefficient of (1 + 0.04)^r which is $728.00.

6 0
3 years ago
PLEASE PLEASE HELPPPPPP
murzikaleks [220]

Answer:

B

Step-by-step explanation:

The rulers tell you the length of the sides

8 0
2 years ago
SOMEONE PLEASE ANSWER ASAP!! 55 POINTS!!
nadezda [96]

Answer:

EG = 16 and FH =22

Step-by-step explanation:

We know that the diagonals of a parallelogram bisect each other

so 2a  = 3b+2

and 2a+3 = 6b-1

We know have a system of equations to solve

2a  = 3b+2

 2a+3 = 6b-1

Subtract 3 from each side

2a+3-3 = 6b-1-3

2a = 6b -4

Now we can set the 2 equations equal  ( 2a  = 3b+2  and 2a = 6b -4)

3b+2 = 6b-4

Subtract 3b from each side

3b-3b+2 = 6b-3b-4

2 = 3b-4

Add 4 to each side

2+4 = 3b-4+4

6 = 3b

Divide by 3

6/3 = 3b/3

2 =b

We want to find a

2a  = 3b+2

Substitute in b=2

2a = 3(2) + 2

2a = 6+2

2a =8

Divide by 2

2a/2 =8/2

a = 4

Now that we know a and b

EG = 2a + 3b+2

    = 2(4) + 3(2)+2

   = 8+6+2

   = 16

FH = 2a+3 + 6b-1

    = 2(4) +3 +6(2)-1

    = 8+3+12-1

   = 23-1

  = 22

4 0
3 years ago
SOMEONE PLZZZ HELP ME THIS IS DUE IN LIKE 5 MINS (I WILL MARK BRAINLIEST)
andrew-mc [135]

Answer:

1) x = 8

2) ∠RPS = 36°

Step-by-step explanation:

<u>GIVEN :-</u>

  • ∠QPS = 180°
  • ∠QPR = 7x + 88
  • ∠RPS = 3x + 12

<u>TO FIND :-</u>

  1. Value of x
  2. Measure of ∠RPS

<u>FACTS TO KNOW BEFORE SOLVING :-</u>

In a straight line , if there are two angles such that their sum is equal to straight angle (or 180° in other words) , then those angles are known as linear pair.

<u>PROCEDURE :-</u>

1)

Measure of ∠QPS = 180° and it comprises of ∠QPR & ∠RPS.

⇒ ∠QPR & ∠RPS are linear pair.

⇒ ∠QPR + ∠RPS = 180°

⇒ 7x + 88 + 3x + 12 = 180°

⇒ 10x + 100 = 180

⇒ 10x = 180 - 100 = 80

⇒ x = 80/10 = 8

2)

x = 8. So,

∠RPS = 3×8 + 12 = 24 + 12 = 36°

8 0
3 years ago
Suppose that a teacher plans to give four students a quiz. The minimum possible score on the quiz is 0, and the maximum possible
denis23 [38]

Answer:

5 is the largest it could possibly be

8 0
3 years ago
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