Answer:
The principal borrow for loan is $1,500 .
Step-by-step explanation:
Given as :
The interest paid on simple interest = s.i = $240
The rate of simple interest applied = r = 4%
The time period for loan = t = 4 years
Let The principal borrow = $p
Now,<u> from Simple Interest method</u>
Simple Interest = 
Or. s.i = 
Or, $240 = 
Or, $240 × 100 = 16 × p
Or, $24000 = 16 × p
∴ p = 
i.e p = $1,500
So, The principal borrow for loan = p = $1,500
Hence, The principal borrow for loan is $1,500 . Answer
9514 1404 393
Answer:
(a) -- the correct choice is highlighted
Step-by-step explanation:
The units of specific heat tell you what quantities make up the ratio.

The temperature will decrease by 2.56 C.
Answer:
6x^2 − 10x − 24
Step-by-step explanation:
2(3x + 4)(x - 3)
(6x + 8)( x − 3)
6x^2 − 18x + 8x − 24
6x^2 − 10x − 24
Answer:
-3x³ - 4x² + x - 9
Step-by-step explanation:
-5x³ + 2x² + x - 7
- <u>(-2x³ + 6x² + 0 + 2)</u> remember: when you subtract, you 'add the opposite'
-3x³ + (-4x²) + x + (-9)