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3 years ago

How to draw model of 3 × 40

Mathematics

1 answer:

dangina [55]3 years ago

7 0

You could try an Array or Area

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I’m confused on this

dexar [7]

$\huge\boxed{x=25}$

The mistake is in Step 1. The solver should have also squared $9$ when squaring the other side of the equation.

<h3>Correctly solving</h3>

$\begin{aligned}\sqrt{3x+6}&=9\\(\sqrt{3x+6})^2&=9^2\\3x+6&=81\\3x+6-6&=81-6\\3x&=75\\\frac{3x}{3}&=\frac{75}{3}\\x&=25\end{aligned}$

4 0

2 years ago

Read 2 more answers

Solve for x<br> 2(4x-3)-8=4+2 x ; x = 3?

frozen [14]

Answer:

x=3

Step-by-step explanation:

7 0

3 years ago

Use the listing method to write the following set.

vampirchik [111]

It’s C because it’s less than 3

3 0

3 years ago

3x - 5y = -35 <br> please solve and show your work

scoray [572]

You use the formula y=mx+b, therefore you have to isolate the y
First you subtract 3x to both sides.
3x - 5y = -35
-3x -3x
Then it would be
-5y = -3x -35
Then you divide -5 on both sides to isolate the y
-5y = -3x -35
/-5 /-5 /-5
Two negatives cancel out and make a positive so it would be
Y = 3/5x + 7
(:

8 0

3 years ago

A batch consists of 12 defective coils and 88 good ones. Find the probability of getting two good coils when two coils are rando

Allushta [10]

<u>Answer:</u>

The probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made is 0.7744

<u>Solution:</u>

Total number of coils = number of good coils + defective coils = 88 + 12 = 100

p(getting two good coils for two selection) = p( getting 2 good coils for first selection ) $\times$ p(getting 2 good coils for second selection)

p(first selection) = p(second selection) = $\frac{\text { number of good coils }}{\text { total number of coils }}$

Hence, p(getting 2 good coil for two selection) = $\frac{88}{100} \times \frac{88}{100} =\bold{0.7744}$

5 0

3 years ago