Answer:
B
Step-by-step explanation:
Using the determinant to determine the type of zeros
Given
f(x) = ax² + bx + c ( a ≠ 0 ) ← in standard form, then the discriminant is
Δ = b² - 4ac
• If b² - 4ac > 0 then 2 real and distinct zeros
• If b² - 4ac = 0 then 2 real and equal zeros
• If b² - 4ac < 0 then 2 complex zeros
Given
f(x) = (x - 1)² + 1 ← expand factor and simplify
= x² - 2x + 1 + 1
= x² - 2x + 2 ← in standard form
with a = 1, b = - 2, c = 2, then
b² - 4ac = (- 2)² - (4 × 1 × 2) = 4 - 8 = - 4
Since b² - 4ac < 0 then the zeros are complex
Thus P(x) has no real zeros
Answer: is in the picture
The answer to -7 +11 -6 + 8 =6
Answer:
option 4
Step-by-step explanation:
Answer:
a. The distance from the center to either vertex
Step-by-step explanation:
The distance from the center to a vertex is the fixed value <em>a</em>. The values of <em>a</em> and <em>c</em> will vary from one ellipse to another, but they are fixed for any given ellipse.
I hope this helps you out alot, and as always, I am joyous to assist anyone at any time.