Ask question

Ask question

All categories

3 years ago

12

Together, teammates Pedro and Ricky got 2681 base hits last season. Pedro had 283 more hits than Ricky. How many hits did each p

layer have

1 answer:

I am Lyosha [343]3 years ago

7 0

Answer:

Ricky had 1199 hits.

Pedro had 1482 hits.

Step-by-step explanation:

<u>State your variables</u>

let "p" be the number of Pedro's base hits

let "r" be the number of Ricky's base hits

<u>Create equations</u> using information from the problem

p + r = 2681 [1]

p = r + 283 [2]

<u>Substitute equation [2] in equation [1]</u> replacing 'p'

p + r = 2681

r + 283 + r = 2681

<u>Combine like terms</u> to simplify

2r + 283 = 2681

<u>Isolate '"r"</u> to solve for Ricky's base hits.

2r + 283 - 283 = 2681 - 283 Subtract 283 on both sides

2r = 2398

2r/2 = 2398/2 Divide both sides by 2

r = 1199 Number of Ricky's hits

Substitute r = 1199 into any equation to find "p". I will use [2].

p = r + 283

p = 1199 + 283 Add

p = 1482 Number of Pedro's hits

Therefore Ricky had 1199 hits and Pedro had 1482 hits.

You might be interested in

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B125%20%7D%20-%20%5Csqrt%7B180%7D%20%2B%20%5Csqrt%7B45%7D%20" id="TexFormula1" tit

Kobotan [32]

Answer:

2 $\sqrt{5}$

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

Simplifying the radicals

$\sqrt{125}$ = $\sqrt{25(5)}$ = $\sqrt{25}$ × $\sqrt{5}$ = 5 $\sqrt{5}$

$\sqrt{180}$ = $\sqrt{36(5)}$ = $\sqrt{36}$ × $\sqrt{5}$ = 6 $\sqrt{5}$

$\sqrt{45}$ = $\sqrt{9(5)}$ = $\sqrt{9}$ × $\sqrt{5}$ = 3 $\sqrt{5}$

Thus

$\sqrt{125}$ - $\sqrt{180}$ + $\sqrt{45}$

= 5 $\sqrt{5}$ - 6 $\sqrt{5}$ + 3 $\sqrt{5}$

= 2 $\sqrt{5}$

3 0

3 years ago

I really Need help solving this problem!

Paraphin [41]

Answer:

Hello,

Answer A : 11.2 ≤ X ≤ 29.2

Step-by-step explanation:

$Z=\dfrac{X-20.2}{4.5} \\\\X=4.5*Z+20.2\\\\For\ Z=-2, \ X=4.5*(-2)+20.2=11.2\\For\ Z=2, \ X=4.5*2+20.2=29.2\\$

8 0

2 years ago

BRAINLIST OPPORTUNITY<br><br> what is the slope of the line on the graph?

Vika [28.1K]

Answer:

2,4

Step-by-step explanation:

go up by 8 then right 16

4 0

3 years ago

Read 2 more answers

How do I solve this puzzle?

Zarrin [17]

Answer: use division

Step-by-step explanation:

8 0

3 years ago

What are the zeros of the function below? F(x)= (x-1)(x+1)/6(x-4)(x+7)

Lisa [10]

Answer:

+1 and -1

Step-by-step explanation:

The function in this problem is:

$f(x)=\frac{(x-1)(x+1)}{6(x-4)(x+7)}$

First of all, we have to define the domain of the function, which is the set of values of x for which the function is defined.

In order to find the domain, we have to require that the denominator is different from zero, so

$6(x-4)(x+7)\neq 0$

which means:

$x\neq 4\\x\neq -7$

So the domain is all values of x, except from 4 and -7.

Now we can solve the problem and find the zeros of the function. The zeros can be found by requiring that the numerator is equal to zero, so:

$(x-1)(x+1)=0$

This is verified if either one of the two factors is equal to zero, therefore:

$x-1=0\\\rightarrow x=+1$

and

$x+1 = 0\\\rightarrow x=-1$

We see that both values are part of the domain, so they are acceptable values: so the zeros of the function are +1 and -1.

7 0

2 years ago