From the two triangle, we can see that triangle ADE is a dilation of triangle ABC by a scale factor of 2.
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
From the diagram:
AB = 3 units, AC = 4 units. Using Pythagoras theorem:
BC² = 3² + 4²
BC = 5 units
AE = 6 units, AD = 8 units. Using Pythagoras theorem:
DE² = 6² + 8²
DE = 10 units
From the two triangle, we can see that triangle ADE is a dilation of triangle ABC by a scale factor of 2.
Find out more on equation at: brainly.com/question/2972832
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Answer: cool!
Step-by-step explanation: ;)
Answer:
is b
Step-by-step explanation:
#2: This function is not defined if the denominator = 0. So, steal the denom. and set it = to 0, and then solve the resulting eqn: 3x-1=0, 3x = 1, x = 1/3.
The domain is the set of all real numbers except for x = 1/3. The range is the set of all real numbers except for y = 0.
#4: this function will not be defined if 16-x^4 is less than 0.
so you must solve the inequality x^4 ≤ 16. Take the 4th root of both sides. The domain is (-2, 2). By all means, check. Suppose x = 1.5. is x^4≤16?
The smallest value y can have is zero, which occurs when x = plus or minus 2.
Answer:
w = 
(Anyone can correct me if I'm wrong)
Step-by-step explanation:
Before we start the solving, we can make the following statements:
Area = l x w
Area = 5x + 25
therefore,
l x w = 5x + 25
Since the question states that the length is x more than the width, so we can make the following statement:
w = l + x
With this, we can substitute it to the first statement we made, l x w = 5x + 25,
l x (l + x) = 5x + 25
+ lx = 5x + 25
lx - 5x = 25 - 
x(l - 5) = 25 - 
x = 
From this, we can find w by substituting it in the statement we made earlier, w = l + x,
w = 