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3 years ago

Expand the polynomial: (6x^2−11y^3)(−6x^2−11y^3)

Mathematics

1 answer:

a_sh-v [17]3 years ago

3 0

on expanding polynomial (6x^2−11y^3)(−6x^2−11y^3) or $(6x^2-11y^3)(-6x^2-11y^3)$ is $121y^6 -36x^4$ .

<u>Step-by-step explanation:</u>

We have , (6x^2−11y^3)(−6x^2−11y^3):

$(6x^2-11y^3)(-6x^2-11y^3)$

⇒ $(6x^2-11y^3)(-6x^2-11y^3)$

We know that :

$(a +b)(c+d) = (ac+ad+ad+bd)$

⇒ $(6x^2(-6x^2) - 11y^3(-6x^2) )+(6x^2(-11y^3) + (-11y^3)(-11y^3))$

⇒ $(-36x^4+66x^2y^3 -66x^2y^3 + 121y^6)$

⇒ $(-36x^4+ 121y^6)$

⇒ $121y^6 -36x^4$

Therefore, on expanding polynomial (6x^2−11y^3)(−6x^2−11y^3) or $(6x^2-11y^3)(-6x^2-11y^3)$ is $121y^6 -36x^4$ .

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The sun produces 3.9 ⋅ 10 to the 33th power ergs of radiant energy per second. How many ergs of radiant energy does the sun prod

arlik [135]

So the sun produces 3.9x10³³/ second

Using this ratio (3.9x10³³/ second) we can use the porpotions to calculate time taken (T) to produce 1.55x10⁷.

$\frac{3.9(10^3) ergs}{1 second} = \frac{1.55(10^7)ergs}{T}$

Then isolate T and find the time

$\frac{T3.9(10^3)ergs}{1 second} = {1.55(10^7)ergs$
$T3.9(10^3)ergs = ({1.55(10^7)ergs)seconds$
$T = \frac{(1.55(10^7)ergs)seconds}{3.9(10^3)ergs}$
$T = \frac{(1.55(10^7)seconds}{3.9(10^3)}$
$T = \frac{1.55}{3.9}(10^4)seconds$
$T = 0.397(10^4)seconds$
$T = 3.97(10^-^1)(10^4)seconds$
$T = 3.97(10^3)seconds$

Thus it took 3.97x10³ seconds for 1.55x10⁷. of ergs to be produced
Hope that helped and if it did, a Brainliest rating would be much appreciated

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3 years ago

A circle has a radius of 6. An arc in this circle has a central angle of 330

sashaice [31]

Answer: $Arc\ lenght\approx34.55\ units$

Step-by-step explanation:

<h3> The complete exercise is: " A circle has a radius of 6. An arc in this circle has a central angle of 330 degrees. What is the arc length?"</h3><h3></h3>

To solve this exercise you need to use the following formula to find the Arc lenght:

$Arc\ lenght=2\pi r(\frac{C}{360})$

Where "C" is the central angle of the arc (in degrees) and "r" is the radius.

In this case, after analize the information given in the exercise, you can identify that the radius and the central angle in degrees, are:

$r=6\ units\\\\C=330$

Therefore, knowing these values, you can substitute them into the formula:

$Arc\ lenght=2\pi (6\ units)(\frac{330}{360})$

And finally,you must evaluate in order to find the Arc lenght.

You get that this is:

$Arc\ lenght=2\pi (6\ units)(\frac{11}{12})\\\\Arc\ lenght=11\pi \ units\\\\Arc\ lenght\approx34.55\ units$

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3 years ago

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Bezzdna [24]

Answer:

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Step-by-step explanation:

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