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lana66690 [7]
2 years ago
7

Expand the polynomial: (6x^2−11y^3)(−6x^2−11y^3)

Mathematics
1 answer:
a_sh-v [17]2 years ago
3 0

on expanding polynomial (6x^2−11y^3)(−6x^2−11y^3) or (6x^2-11y^3)(-6x^2-11y^3) is 121y^6 -36x^4 .

<u>Step-by-step explanation:</u>

We have , (6x^2−11y^3)(−6x^2−11y^3):

(6x^2-11y^3)(-6x^2-11y^3)

⇒ (6x^2-11y^3)(-6x^2-11y^3)

We know that :

(a +b)(c+d) = (ac+ad+ad+bd)

⇒ (6x^2(-6x^2)  - 11y^3(-6x^2) )+(6x^2(-11y^3) + (-11y^3)(-11y^3))

⇒ (-36x^4+66x^2y^3 -66x^2y^3  + 121y^6)

⇒ (-36x^4+ 121y^6)

⇒ 121y^6 -36x^4

Therefore, on expanding polynomial (6x^2−11y^3)(−6x^2−11y^3) or (6x^2-11y^3)(-6x^2-11y^3) is 121y^6 -36x^4 .

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A typical high school student consumes 67.5 pounds of sugar per year. As part of a new nutrition plan, each member of the track
tino4ka555 [31]

Answer:

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Step-by-step explanation:

We know that they start off with 67.5 pounds of sugar and they need to reduce it by 20%. We also know from the problem that we want to know the MAXIMUM amount of sugar consumed by each track member.

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Vladimir79 [104]
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