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Burka [1]
4 years ago
10

A factory can produce small wheels for the mousetrap cars at a rate of 18,000 wheels in 3 hours .What is the unit rate per hour?

Mathematics
2 answers:
zimovet [89]4 years ago
7 0
To find the unit rate per hour you divide 18, 000 wheels by 3 hours

which is 6000 wheels per hour
igomit [66]4 years ago
6 0
The answer is 18000/3=6000
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EASY WILL GIVE BRAINLEIST
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Answer:75,000 x 5 = 5 x 75,000

Step-by-step explanation:

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KM and NP are parallel lines.<br><br> Which angles are alternate exterior angles?
suter [353]

Answer:

<MLJ and <NOQ

Step-by-step explanation:

Alternate exterior angles are angles that lie outside of the two parallel lines that are cut across by the transversal line, and are also alternating each other along the transversal

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3 years ago
An orange juice producer buys oranges from a large orange grove that has one variety of orange. The amount of juice squeezed fro
skad [1K]

Answer:

The probability is 70% that the sample mean amount of juice will be contained between 4.9168 ounces and 5.0832 ounces.

Step-by-step explanation:

To solve this question, the Normal probability distribution and the Central Limit Theorem are important.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 5, \sigma = 0.4, n = 25, s = \frac{0.4}{\sqrt{25}} = 0.08

The probability is 70% that the sample mean amount of juice will be contained between what two values symmetrically distributed around the population mean?

The lower end of this interval is the value of X when Z has a pvalue of 0.5 - 0.7/2 = 0.15

The upper end of this interval is the value of X when Z has a pvalue of 0.5 + 0.7/2 = 0.85

Lower end

X when Z has a pvalue of 0.15. So X when Z = -1.04.

Z = \frac{X - \mu}{\sigma}

Due to the Central Limit Theorem

Z = \frac{X - \mu}{s}

-1.04 = \frac{X - 5}{0.08}

X - 5 = -1.04*0.08

X = 4.9168

Upper end

X when Z has a pvalue of 0.15. So X when Z = 1.04.

Z = \frac{X - \mu}{\sigma}

Due to the Central Limit Theorem

Z = \frac{X - \mu}{s}

1.04 = \frac{X - 5}{0.08}

X - 5 = 1.04*0.08

X = 5.0832

The probability is 70% that the sample mean amount of juice will be contained between 4.9168 ounces and 5.0832 ounces.

6 0
3 years ago
Five Times the difference of a number and 3 is 17
frosja888 [35]
5(x-3)=17
x-3=3.4
x=6.4
8 0
3 years ago
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