Jenny is 12 years older than Nancy. Five years ago Jenny was three times as old as Nancy. How old is each now?

Commission: 10 percent on first $5,000; 15% over $5,000. Find the total graduate commission on $22,000.

natta225 [31]

Based on the information about the percentage, the commission that will be paid will be $3050.

<h3>How to solve percentage</h3>

From the information given, it was stated that there's a 10 percent on first $5,000 and 15% over $5,000.

The total graduate commission on $22,000 will be:

= (10% × $5000) + (15% × $17000)

= (0.1 × $5000) + (0.15 × $17000)

= $500 + $2550

= $3050

Learn more about percentages on:

brainly.com/question/24304697

8 0

2 years ago

Ms.Omar runs the school tennis club. She has a bin of tennis balls and rackets. For every 5 tennis balls in the bin, there are 3

stepan [7]

Answer:

see the explanation

Step-by-step explanation:

Let

x ----> number of tennis balls

y ----> number of tennis rackets

we know that

To find out the ratio of tennis balls to tennis rackets, divide the number of tennis ball by the number of tennis rackets

In this problem we have

$\frac{x}{y}=\frac{5}{3}$

so

$x=\frac{5}{3}y$

That means

The number of tennis balls is three-fifths times the number of tennis rackets

see the attached figure to better understand the problem

8 0

2 years ago

Drew invests $70.00. It earns 50% interest annually.

VladimirAG [237]

Step-by-step explanation:

50% interest annually.

that means he gets 50% interest of the invested capital every year.

and that means he gets 50% of $70 in one year.

70 = 100%

1% = 100%/100 = 70/100 = $0.70

50% = 1%×50 = 0.7 × 50 = $35

he will earn $35 interest in one year.

as you noticed: 50% simply means 1/2 (as 100% stands for the whole).

3 0

1 year ago

1. A report from the Secretary of Health and Human Services stated that 70% of single-vehicle traffic fatalities that occur at n

Nuetrik [128]

Using the binomial distribution, it is found that there is a 0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

For each fatality, there are only two possible outcomes, either it involved an intoxicated driver, or it did not. The probability of a fatality involving an intoxicated driver is independent of any other fatality, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

70% of fatalities involve an intoxicated driver, hence $p = 0.7$ .

A sample of 15 fatalities is taken, hence $n = 15$ .

The probability is:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)$

Hence

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{15,10}.(0.7)^{10}.(0.3)^{5} = 0.2061$

$P(X = 11) = C_{15,11}.(0.7)^{11}.(0.3)^{4} = 0.2186$

$P(X = 12) = C_{15,12}.(0.7)^{12}.(0.3)^{3} = 0.1700$

$P(X = 13) = C_{15,13}.(0.7)^{13}.(0.3)^{2} = 0.0916$

$P(X = 14) = C_{15,14}.(0.7)^{14}.(0.3)^{1} = 0.0305$

$P(X = 15) = C_{15,15}.(0.7)^{15}.(0.3)^{0} = 0.0047$

Then:

$P(10 \leq X \leq 15) = P(X = 10) + P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15) = 0.2061 + 0.2186 + 0.1700 + 0.0916 + 0.0305 + 0.0047 = 0.7215$

0.7215 = 72.15% probability that between 10 and 15, inclusive, accidents involved drivers who were intoxicated.

A similar problem is given at brainly.com/question/24863377

5 0

2 years ago

HELP ME PLEASEEEEEEEEEEEEEEEE

hoa [83]

90 mm ..................

5 0

3 years ago

Read 2 more answers