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max2010maxim [7]
3 years ago
14

How many degrees does the polynomial 6c9 have

Mathematics
2 answers:
spayn [35]3 years ago
6 0

Answer:

None, there are no degrees/exponents

Step-by-step explanation:

Hope this is helpful :)

torisob [31]3 years ago
4 0

Answer:

has three terms. The first term has a degree of 5 (the sum of the powers 2 and 3), the second term has a degree of 1, and the last term has a degree of 0. Therefore, the polynomial has a degree of 5, which is the highest degree of any term

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Please help me with these. These are so hard.<br><br>​
LuckyWell [14K]

\bf \textit{difference and sum of cubes} \\\\ a^3+b^3 = (a+b)(a^2-ab+b^2) ~\hfill a^3-b^3 = (a-b)(a^2+ab+b^2) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \boxed{a^6+b^6}\implies a^{2\cdot 3}+b^{2\cdot 3}\implies (a^2)^3+(b^2)^3 \\[2em] [a^2+b^2] [(a^2)^2-a^2b^2+(b^2)^2]\implies \boxed{(a^2+b^2)(a^4-a^2b^2+b^4)}

about the second one... well, is a "fait accompli" that using the pythagorean theorem, if x = 8 and y = 5, the hypotenuse must be √(8² + 5²) = √(89), which is neither of those choices.

5, 8, 13 are no dice, namely 5² + 8² ≠ 13

25, 64, 17 is are no dice too, because 25² + 17² ≠ 64²

however, 5,12 and 13 are indeed a pythagorean triple

also is 39, 80, 89.

when looking for a pythagorean triple, recall that c² = a² + b².

so the longest leg is the sum of the square of the small ones.

so what you'd do is, check the small legs, square them, add them up, if they're indeed a pythagorean triple, they "must" add up to the longest leg.

4 0
3 years ago
What is the best way to solve this
Komok [63]
Make 2 equations one for the price and one for quantity.  so first set x = AA and y= AAA. for price 37= 1x+.75y. now for the quantity we have x+y=42. Now we can solve by subtracting the equation for price from the equation for quantity and we get .25y =5. solving this we get y= 20. Now we plug that value back in and solve for x. 22 double A's and 20 triple A's.
6 0
3 years ago
The measure of angle A to the nearest tenth of a degree is: A 18.5 B 19.5 C 20.5
Andrew [12]

Answer:

B


Step-by-step explanation:

<u>This is a right triangle as shown by the right angle.</u>

  • The side opposite the right angle is the hypotenuse, which is 9.
  • The side opposite angle A is 3.

So we have the opposite of A and the hypotenuse.

The trigonometric ratio that relates opposite side to hypotenuse is SINE.

sin\theta=\frac{opposite}{hypotenuse}

Since, we need angle A, \theta is A, opposite side is 3, and hypotenuse is 9, we substitute:

sinA=\frac{3}{9}\\sinA=\frac{1}{3}

<em>To solve for the angle, we use our calculator and find the inverse sin of \frac{1}{3} :</em>

A=sin^{-1}(\frac{1}{3})\\A=19.47

<em>Rounding to nearest tenth of a degree:</em>

A=19.5

B is the right choice.

6 0
3 years ago
I need help, if you know this plz help me. cuz i'm lost. Thankssss
Musya8 [376]

Answer:

Are there directions?

Step-by-step explanation:

6 0
3 years ago
8u^8+(-21u^8)<br> Helpppp quick
ELEN [110]

\huge\textsf{Hey there!}

\mathsf{8u^8 + (-21u^8)}\\\mathsf{= 8u^2 - 21u^8}\\\large\textsf{COMBINE the LIKE TERMS}\\\mathsf{=(8u^8 - 21u^8)}\\\mathsf{= 8 - 21\rightarrow\boxed{\bf -13}}\\\mathsf{= 8u^2 - 21u^8 \rightarrow \bf -13u^8}\\\\\\\\\boxed{\boxed{\large\textsf{Answer: \bf -13u}\bf ^2}}\huge\checkmark\\\\\\\\\large\textsf{Good luck on your assignment and enjoy your day!}\\\\\\\frak{Amphitrite1040:)}

5 0
3 years ago
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