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vfiekz [6]
2 years ago
5

Compare the models for 1/3 and 2/6 how dose the number of parts relate to the sizes of the parts

Mathematics
1 answer:
Elanso [62]2 years ago
6 0
There is no model attached, but, we can imagine a model.
Take a whole pizza.
There’s six slices and you have three friends.
You want it to be even and so each friend gets two slices.
But, originally, the pizza could’ve been sliced into three bigger pieces anyways.
1/3 = 2/6
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A circle is cut into congruent sections and arranged to form a figure that approximates a parallelogram. Find the approximate he
Solnce55 [7]

Answer:

<h2>The height is 3.43 centimeters, approximately.</h2>

Step-by-step explanation:

Notice that there are 16 pieces from the circle, which means each sector has an angle of

\theta = \frac{360\°}{16}=22.5\°

Where all sectors have equal area.

Now, the area of the whole circle is 12.25 \pi \ cm^{2}, if we use the formula of its area, we'll find the radius of the circle

A= \pi r^{2}\\ 12.25\pi = \pi r^{2}\\ r=\sqrt{12.25} \approx  3.5

Notice that each piece works as an isosceles triangle, because each side is the radius, that is, they have the same length. So far, we know the sides of the isosceles triangle and one internal angle.

To find the height of the one piece, we need to use trigonometric reasons, because the height divides a triangle in two equal right triangles.

cos(11.25\°)=\frac{h}{3.5}\\ h=3.5 \times cos(11.25 \°)\\h \approx 3.43

Therefore, the height is 3.43 centimeters, approximately.

6 0
3 years ago
Colton swam once along the length of a pool that has a perimeter of 124 yd. The width of the pool is 20 yd. How many feet did Co
Vesna [10]
If I could give you an answer, I would. But I'm terrible at Math so, sorry
3 0
3 years ago
Read 2 more answers
Please help with this problem i need to show my work
Damm [24]

Answer:

2/7 .2857

Step-by-step explanation:

5 0
3 years ago
if you save three pennies on January 1, six pennies on January 2, nine pennies on January 3, and continue this pattern for one y
Katarina [22]

Answer:

2003.85

Step-by-step explanation:

I realize I'm a year late, but the math of the previous answer was so terrible I'm honestly too horrified to let this be.

You have save by an increasing amount of 3 pennies per day. You start with 3 and build from that, each day, for 365 days. First, you must figure out what amount of pennies you shoved into your account on the final 365th day.

An= a1+(n-1)d

An=term you want

a1= term you begin with

n= term you want

d= constant amount

A_365= 3 + (365-1)*3

A_365= 1095

Arithmetic Sum: Sn = N/2 (a1 + an)

365/2 * (3 + 1095) = 200385.

This means you've invested a total of 200385 PENNIES after 365 days.

The question asks for dollars, not your rusting lincoln's.

As (I hope) you know, 1 Dollar = 100 pennies

200385 pennies/100 = 2003.85.

This means you have $2003.85 in your account by the conclusion of the 365th day.

4 0
3 years ago
Consider the two data sets below:
alina1380 [7]

Answer:

<u><em>Option c) The data sets will have the same values of their interquartile range.</em></u>

<u><em></em></u>

Explanation:

<u>1. The values are in order: </u>they are in increasing oder, from lowest to highest value.

<u>2. Calculate the interquartile range.</u>

<em />

<em>Interquartile range</em>, IQR, is the third quartile, Q3, less the first quartile Q1:

  • IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

<u>Data Set 1</u>: 19, 25, 35, 38, 41, 49, 50, 52, 59

             [19, 25, 35, 38],  41,  [49, 50, 52, 59]

                                         ↑

                                     median = 41

   

<u>Data Set 2</u>: 19, 25, 35, 38, 41, 49, 50, 52, 99

             [19, 25, 35, 38] , 41,  [49, 50, 52, 99]

                                         ↑

                                      median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: <u>First quartile</u>

                [19, 25, 35, 38],

                            ↑

                           Q1 = [25 + 35] / 2 = 30

                   <u>Third quartile</u>

                   [49, 50, 52, 59]

                                ↑

                                Q3 = [50 + 52] / 2 = 51

                     IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: <u> First quartile</u>

                   [19, 25, 35, 38]

                               ↑

                               Q1 = [25 + 35] / 2= 30

                  <u>Third quartile</u>

                   [49, 50, 52, 99]

                                ↑

                                Q3 = [52 + 50]/2 = 51

                   IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

<em>An outlier will change the range</em> because the range is the maximum value less the minimum value.

5 0
2 years ago
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