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DENIUS [597]
3 years ago
10

The area of jacksons rectangular garden is 64 square ft. If the length of the

Mathematics
2 answers:
Gekata [30.6K]3 years ago
4 0

Hi,

First we must go back to the formula of the Area of a 2d figure which is L*W or Length times the Width. So, we could divide 64 by 16.

64/16 = 4

The answer is 4.

weeeeeb [17]3 years ago
3 0

width=4

64  \div 16 = 4

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What is 18 2 rounded to the nearest whole number?<br> 56
Tju [1.3M]

Answer: 18

Step-by-step explanation: 18.2 rounded to the nearest whole number is 18. A whole number does not contain a decimal, so you can simply eliminate the decimal and the numbers after it.

7 0
4 years ago
Please give the right answer and show work if possible
Step2247 [10]

Answer:

14

Step-by-step explanation:

Sin(∅) = Opposite angle ÷ hypotenuse.

Sin (45) = 7\sqrt{2} ÷ hypotenuse

hypotenuse = 7\sqrt{2} ÷ sin(45)

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Keep in mind

sin(45) = √2÷2

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so we have:  Hypotenuse = 7√2 ÷ (√2÷2)

Hypotenuse= 14.

6 0
3 years ago
What is the interquartile range of 4 5 7 9 10 14 16 24
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2's and 3's of GCF


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7 0
3 years ago
Read 2 more answers
What is the area of a regular hexagon with a distance from its center to a vertex of 1 cm? (Hint: A regular hexagon can be divid
devlian [24]
<h3>Answer:</h3><h3>Exact area = \frac{3}{2}\sqrt{3} square cm</h3><h3>Approximate area = 2.598 square cm</h3>

=================================================

Work Shown:

s = side length of equilateral triangle = 1 cm

A = area of equilateral triangle with side length 's'

A = \frac{\sqrt{3}}{4}*s^2

A = \frac{\sqrt{3}}{4}*1^2

A = \frac{\sqrt{3}}{4}

This is just one of the 6 equilateral triangles (see diagram below)

Multiply by 6 to get the area of all 6 equilateral triangles, or the entire hexagonal area

6*A = 6*\frac{\sqrt{3}}{4}

6A = \frac{3\sqrt{3}}{2}

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4 0
3 years ago
The length of a rectangle is 5 feet more than twice the width. The perimeter is 130 feet. Find the dimensions.
Dahasolnce [82]
So,

The problem tells us that the length of the rectangle is 5 feet more than twice the width.
Mathematically:
length = 5 + 2width
l = 5 + 2w


We know that the perimeter is 2l + 2w.
2l + 2w = 130

2(5 + 2w) + 2w = 130

Distribute
10 + 4w + 2w = 130

Collect Like Terms
10 + 6w = 130

Subtract 10 from both sides
6w = 120

Divide both sides by 6
w = 20

The width is 20.


Since
l = 5 + 2w

Substitute
l = 5 + 2(20)

Multiply
l = 5 + 40

Collect Like Terms
l = 45

The length is 45.

Check
2l + 2w = 130

2(45) + 2(20) = 130

90 + 40 = 130

130 = 130

Width: 20 ft.
Length: 45 ft.
5 0
3 years ago
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