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Pavel [41]
3 years ago
6

Find 3x-y-3z x=-2 y=1 and z=-2

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
8 0
Just fill in the problem... 3*-2-1-3*-2
timama [110]3 years ago
7 0
<span>3x - y - 3z
 x=-2 y=1  z=-2

=>3 X -2 - 1 - 3 X -2
=> -6 - 1 + 6
=> -1

Hope it helps !!!</span>
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Alisiya [41]

Answer:

The length of the diagonal HJ is 10.82 units

Step-by-step explanation:

* Lets revise the rule of the distance between two points

- d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}, where

 (x_{1},y_{1}) and (x_{2},y_{2}) are the two points

* Lets use this rule to find the length of the diagonal HJ

∵ The coordinates of point H are (-4 , 3)

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∴ x_{1}=-4 and x_{2}=5

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- Lets find the length of the diagonal HJ by using the rule above

∴ HJ = \sqrt{(5-(-4))^{2}+(-3-3)^{2}}=\sqrt{(5+4)^{2}+(-6)^{2}}

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∴ HJ = 10.82

* The length of the diagonal HJ is 10.82 units

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