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sergiy2304 [10]
2 years ago
13

A rectangle garden has a length that is six feet more than twice it’s width. It takes 120 feet of fencing to completely enclose

the garden’s area. What equation could be used to find the width of the garden ?
Mathematics
1 answer:
solniwko [45]2 years ago
3 0

Answer:

      3w = 54

Step-by-step explanation:

Let the width of the garden be w

Length = 2w + 6

Perimeter = 120 feet

2* (length + Width) = 120

2*(2w + 6 + w) = 120

       3w + 6    = 120/2

       3w + 6    = 60

              3w = 60 - 6

              3w = 54

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The answer is letter B.
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3 years ago
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What is the value of x? <br><br> A. 68° <br> B. 62° <br> C. 112° <br> D. 124
bearhunter [10]
The triangle drawn in the question shows a small single line drawn across two sides of the triangle.

This means that those two sides are equal in length.

Hence, the triangle is an isosceles triangle.

In isosceles triangles, the angles opposite to the equal sides are also equal.

Hence, we know that the two angles other than x is 56°.

The sum of the interior angles of a triangle is 180°

x + 56 + 56 = 180

x = 180 - 56 - 56

x = 180 - 112

x = 68°

Hence, the answer is A.
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3 years ago
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1) A family consisting of three persons—A, B, and C—goes to a medical clinic that always has a doctor at each of stations 1, 2,
crimeas [40]

Answer:

Step-by-step explanation:

Let us record the station number 1, 2 or 3 for each family member A, B or C.

I am attaching a table containing total outcomes. Outcomes are presented along rows while the assigned station to each member is written along columns. For ease of understanding, 1 3 2 in the table should be interpreted as family member A being assigned to station 1, member B to station 3 and member C to station number 2, respectively.

From table it is clear that the total outcomes possible are 27.

We know that, probability can be defined as,

PROBABITILY = \frac{NUMBER\;OF\;DESIRED\;OUTCOMES}{TOTAL\;NUMBER\;OF\;OUTCOMES}

a) All Members Assigned to the Same Station.

Cases for all members being assigned to same station are as follows:

[1 1 1], [2 2 2], [3 3 3] (outcome number 1, 14 and 27 in the table).

Therefore,

PROBABILITY\;(Case\;a) = \frac{3}{27}\\\\PROBABILITY\;(Case\;a) = 0.111

b) At Most Two Members Assigned to the Same Station.

It means that maximum of 2 members can have the same station. Cases for this situation are as follows:

[1 1 2], [1 1 3], [1 2 1], [1 2 2], [1 3 1], [1 3 3], [2 1 1], [2 1 2], [2 2 1], [2 2 3], [2 3 2],

[2 3 3], [3 1 1], [3 1 3], [3 2 2], [3 2 3], [3 3 1], [3 3 2]

(outcome number 2, 3, 4, 5, 7, 9, 10, 11, 13, 15, 17, 18, 19, 21, 23, 24, 25 and 26 in the table).

Therefore,

PROBABILITY\;(Case\;b) = \frac{18}{27}\\\\PROBABILITY\;(Case\;b) = 0.666

c) All Members Assigned to a Different Station.

For this scenario, we have the following results:

[1 2 3], [1 3 2], [2 1 3], [2 3 1], [3 1 2], [3 2 1] (outcome number 6, 8, 12, 16, 20 and 22 in the table).

Therefore,

PROBABILITY\;(Case\;c) = \frac{6}{27}\\\\PROBABILITY\;(Case\;c) = 0.222

3 0
3 years ago
How would you solve this problem? (Worth 10 points, pls help!)
mrs_skeptik [129]

Answer:

(22,0)

Step-by-step explanation:

1. Select any two points given and find their slope (rise/run)

       (-38, 40) and (-23, 30)

      slope =   \frac{40-30}{-38-(-23)} = - 2/3

2. Use the slope and one of the points to create an equation of the line in the format y = mx + b, where m = slope and b = y-intercept.

    y = mx + b ⇒ 40 = -2/3 (-38) + b

3. Solve for b

   40 = -2/3 (-38) + b

   40 = 76/3 + b

   40 - 76/3 = b

   b = 44/3

4. To find the x-intercept, set y = 0, and solve.

   y = -2/3 x + 44/3

   0 = -2/3 x + 44/3

   2/3 x = 44/3

   x = 22

Hope this helped!

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2 years ago
Archimedes was asked by his king to figure out a way of telling if people were giving him fake gold objects. That was when Archi
klio [65]

Answer:

See explanation below

Step-by-step explanation:

Archimedes was able o obtain the actual volume of the supposedly gold made object by collecting the water displaced by the object as it was sunk on a bowl filled with water to the rim. Then knowing the volume displaced and therefore the volume of the object, he could find the object's density (mass over volume). The mass he could get just by weighting the object. and compare that with the density of any other object made of real gold (like for example a coin) and see if the quotient was the same. The density of both objects should be the same if they are made of the same material.

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3 years ago
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