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kvv77 [185]
3 years ago
14

Please tell me which ones I should select!!!

Mathematics
1 answer:
Dvinal [7]3 years ago
5 0

Answer:

0 and -2

Step-by-step explanation:

try that that should work for you even if you have a dad that dose not trust you

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Tim had three toys and Sheila have four toys how many did they have together ?
Ainat [17]

Answer:

7 toys

Step-by-step explanation:

3+4=7

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This is pretty easy :0
maksim [4K]

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1, 1.5, -1 1/5

Step-by-step explanation:

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In November 2010 the average price of 5 gallons of regular unleaded gasoline in the United states was $14.46. what was the price
Lapatulllka [165]

Propecia:

5 gallons ====== $ 14.46.

16 gallons ======= x dollars

X=16*14.46: 5=46.27  

Answer: $ 46.27.

3 0
3 years ago
Which is equivalent to 10/12?options: 10/18 5/6 3/12 9/11
RideAnS [48]

Answer:

5/6 is equivalent to 10/12

Step-by-step explanation:

Hope this helped :)

7 0
2 years ago
For each given p, let ???? have a binomial distribution with parameters p and ????. Suppose that ???? is itself binomially distr
pshichka [43]

Answer:

See the proof below.

Step-by-step explanation:

Assuming this complete question: "For each given p, let Z have a binomial distribution with parameters p and N. Suppose that N is itself binomially distributed with parameters q and M. Formulate Z as a random sum and show that Z has a binomial distribution with parameters pq and M."

Solution to the problem

For this case we can assume that we have N independent variables X_i with the following distribution:

X_i Bin (1,p) = Be(p) bernoulli on this case with probability of success p, and all the N variables are independent distributed. We can define the random variable Z like this:

Z = \sum_{i=1}^N X_i

From the info given we know that N \sim Bin (M,q)

We need to proof that Z \sim Bin (M, pq) by the definition of binomial random variable then we need to show that:

E(Z) = Mpq

Var (Z) = Mpq(1-pq)

The deduction is based on the definition of independent random variables, we can do this:

E(Z) = E(N) E(X) = Mq (p)= Mpq

And for the variance of Z we can do this:

Var(Z)_ = E(N) Var(X) + Var (N) [E(X)]^2

Var(Z) =Mpq [p(1-p)] + Mq(1-q) p^2

And if we take common factor Mpq we got:

Var(Z) =Mpq [(1-p) + (1-q)p]= Mpq[1-p +p-pq]= Mpq[1-pq]

And as we can see then we can conclude that   Z \sim Bin (M, pq)

8 0
3 years ago
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