<span>N(t) = 16t ; Distance north of spot at time t for the liner.
W(t) = 14(t-1); Distance west of spot at time t for the tanker.
d(t) = sqrt(N(t)^2 + W(t)^2) ; Distance between both ships at time t.
Let's create a function to express the distance north of the spot that the luxury liner is at time t. We will use the value t as representing "the number of hours since 2 p.m." Since the liner was there at exactly 2 p.m. and is traveling 16 kph, the function is
N(t) = 16t
Now let's create the same function for how far west the tanker is from the spot. Since the tanker was there at 3 p.m. (t = 1 by the definition above), the function is slightly more complicated, and is
W(t) = 14(t-1)
The distance between the 2 ships is easy. Just use the pythagorean theorem. So
d(t) = sqrt(N(t)^2 + W(t)^2)
If you want the function for d() to be expanded, just substitute the other functions, so
d(t) = sqrt((16t)^2 + (14(t-1))^2)
d(t) = sqrt(256t^2 + (14t-14)^2)
d(t) = sqrt(256t^2 + (196t^2 - 392t + 196) )
d(t) = sqrt(452t^2 - 392t + 196)</span>
P = 2(L + W)
P = 180
W = L - 24
now we sub
180 = 2(L + L - 24)
180 = 2(2L - 24)
180 = 4L - 48
180 + 48 = 4L
228 = 4L
228/4 = L
57 = L
W = L - 24
W = 57 - 24
W = 33
so ur length (L) = 57 ft and ur width (W) = 33 ft
Answer:
i can;t copy or paste either bro
Step-by-step explanation:
Answer: His average speed is 8 miles an hour
Step-by-step explanation: First, two halves make a whole, so we simply multiply how many miles he ran in half an hour by 2!
4 x 2 = 8
Hope this helps :)
