What is the output of adding 1001011 and 100000?

All of the following are the four more widely social media networks discussed in the text EXCEPT:

Elan Coil [88]

The answer is E) Groupon

8 0

3 years ago

Byte pair encoding is a data encoding technique. The encoding algorithm looks for pairs of characters that appear in the string

nika2105 [10]

Answer:

The encoding algorithm looks for pairs of characters that appear in the string more than once and replaces each instance of that pair with a corresponding character that does not appear in the string. ... Byte pair encoding is an example of a lossy transformation because it discards some of the data in the original string.

Explanation:

hope it helps!!

6 0

2 years ago

What does it mean to prioritize tasks?

salantis [7]

Answer:

to rank tasks from most to least important

Explanation:

Prioritize means to choose priority, obviously and priority is the thing is the thing which, among other things, have the biggest importance.

Every day, especially in business, one finds himself swimming in tasks up to his neck. Obviously, not all of them can be successfully finished, or at least not without sacrificing one's personal life or sleep.

Prioritizing, therefore, serves as a helpful organising tool. After writing down all tasks that need to be done, a person should rank them by priority, which means that only urgent and important tasks will be dealt with immediately. Tasks of lower priority will be postponed, delegated or simply deleted.

6 0

2 years ago

Read 2 more answers

Perform algorithm time measurement for all three quadratic sorting algorithms for Best Case (already sorted), Average Case (rand

Kaylis [27]

Answer:

Experiment size : 50,000

==================================

Selection sort :

---------------------------------------------------------

Worst case : 0.162

Average case : 0.116

Best case : 0.080

Insertion sort :

---------------------------------------------------------

Worst case : 0.162

Average case : 0.116

Best case : 0.080

Bubble sort:

--------------------------------------------------------

Worst case : 0.211

Average case : 0.154

Best case : 0.117

Experiment size : 100,000

==================================

Selection sort :

---------------------------------------------------------

Worst case : 0.316

Average case : 0.317

Best case : 0.316

Insertion sort :

---------------------------------------------------------

Worst case : 0.316

Average case : 0.317

Best case : 0.316

Bubble sort:

--------------------------------------------------------

Worst case : 0.482

Average case: 0.487

Best case : 0.480.

Experiment size : 200,000

==================================

Selection sort :

---------------------------------------------------------

Worst case : 1.254

Average case : 1.246

Best case : 1.259

Insertion sort :

---------------------------------------------------------

Worst case : 1.254

Average case : 1.246

Best case : 1.259

Bubble sort:

--------------------------------------------------------

Worst case : 1.990

Average case : 2.009.

Best case : 1.950

Explanation:

[NB: since it is very long there is the need for me to put it it a document form. Kindly check the doc. Files. The file A is the sort Analysis.Java file and the file B is the sort.Java file].

The concept of algorithm time measurement strictly depends on the following;

=> The measurement of time, space or energy on different sizes.

=> Plotting of the measurements and characterizing them.

=> Running or implementation of the algorithm.

Programming language such as Java can be used in accessing the operating system clock and Java had two static methods.

KINDLY CHECK BELOW FOR THE ATTACHMENT.

Download doc

5 0

3 years ago

Create a class called Fraction. Provide a constructor that takes 2 integers. Provide methods for:

tekilochka [14]

Answer:

Explanation;

else

System.out.println("f1 and f2 are not equal");

switch (input.charAt(0)

{

case '+':

f3 = f1.add(f2);

System.out.println("f1+f2=" + f3);

break;

case '-':

f3 = f1.subtract(f2);

System.out.println("f1-f2=" + f3);

break;

case '*':

f3 = f1.multiply(f2);

System.out.println("f1*f2="+f3);

break;

case '/':

f3 = f1.divide(f2);

System.out.println("f1/f2="+f3);

break;

default:

System.out.println("Illegal command: " + input );

break;

}

}// end of while loop

} // end of main

}

Note ; this is the last part of the programme check the attachment from 1-5 this is the 6th .

8 0

3 years ago