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wel
3 years ago
15

A family has two cars. During one particular week, the first car consumed 40 gallons of gas and the second consumed 35 gallons o

f gas. The two cars drove a combined total of 2125 miles, and the sum of their fuel efficiencies was 55 miles per gallon. What were the fuel efficiencies of each of the cars that week?
Mathematics
1 answer:
zmey [24]3 years ago
3 0

Answer:

Car 1 : 40 gallons

Car 2 : 15 gallons

Step-by-step explanation:

F = Car 1 Fuel Efficiency

S = Car 2 Fuel Efficiency

F + S = 55

40F + 35S = 2125

Using the first equation...

S = 55 - F

Then substitute into the second equation.

40F + 35(55 - F) = 2125

Simplify

40F + 1925 - 35F = 2125

5F + 1925 = 2125

5F = 200

F = 40

Then plug it back into S = 55 - F

S = 15

Plug it back into F + S = 55 to check.

Hope this helps.

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This morning, some dragons, horses, and chickens were playing in my backyard. I counted 15 heads, 50 legs, and 4 wings. How many
klasskru [66]

We are given

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we know that

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Let's assume

number of dragons is x

number of horses is y

number of chickens is z

so, we will get

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3x+y+z=15

number of legs =50

any healthy dragon has four legs

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4x+4y+2z=50

we can simplify it

2(2x+2y+z)=50

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now, we can find third equation

dragon has two wings

horse has no wings

chicken has two wings

so, we will get third equations as

2x+0y+2z=4

now, we can simplify it

2x+2z=4

2(x+z)=4

x+z=2

so, we will get system of equations as

3x+y+z=15

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now, we can use substitution

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we can plug this in first equation

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now, we can solve for y

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x-4x+26=23

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3 years ago
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