Find the value of x 2-x7=25
1 answer:
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For the first part:
Every shirt she grabs, will cost her dollars, so if she grabs 3 shirts, then the cost of the shirts is:
With the same rationale, if she grabs 2 pairs of jeans, the cost of the jeans is:
So, her total is:
If you subtract 3 from the total, then the expression is:
For the second part:
If she's paying 3 less for each shirt, then the cost of 3 shirts will become:
In the same fashion, for the two jeans:
So the expression for the total cost is:
For number three:
The amounts are different because the cost of the total purchase is different than the cost of each element that makes up the total purchase.
For number four:
If you're the owner, you want to give the smallest amount of discount (the one in part 1/a).
So you could clarify by saying there's 3 dollars of the TOTAL purchase's cost.
Every shirt she grabs, will cost her dollars, so if she grabs 3 shirts, then the cost of the shirts is:
With the same rationale, if she grabs 2 pairs of jeans, the cost of the jeans is:
So, her total is:
If you subtract 3 from the total, then the expression is:
For the second part:
If she's paying 3 less for each shirt, then the cost of 3 shirts will become:
In the same fashion, for the two jeans:
So the expression for the total cost is:
For number three:
The amounts are different because the cost of the total purchase is different than the cost of each element that makes up the total purchase.
For number four:
If you're the owner, you want to give the smallest amount of discount (the one in part 1/a).
So you could clarify by saying there's 3 dollars of the TOTAL purchase's cost.
Answer:
Horizontal asymptote of the graph of the function f(x) = (8x^3+2)/(2x^3+x) is at y=4
Step-by-step explanation:
I attached the graph of the function.
Graphically, it can be seen that the horizontal asymptote of the graph of the function is at y=4. There is also a <em>vertical </em>asymptote at x=0
When denominator's degree (3) is the same as the nominator's degree (3) then the horizontal asymptote is at (numerator's leading coefficient (8) divided by denominator's lading coefficient (2))
