Question

Which of the following is a valid exclusion for the algebraic fraction 8ab^2x/4a^2b-8ab^2

Answer 1

Answer:

a ≠ 2b

Step-by-step explanation:

The given expression is

$\frac{8ab^{2}x}{4a^{2}b-8ab^{2}}$

$=\frac{8ab^{2}x}{4ab(a-2b)}$

Simplifying it, we have

$\frac{8ab^{2}x}{4a^{2}b-8ab^{2}} = \frac{bx}{a-2b}$

For the above fraction to exist, the denominator must not be equal to zero.

i.e, a-2b ≠ 0

=> a≠2b

∴ The algebraic fraction exists when a≠2b.

Answer 2

Answer:

A valid exclusion for the algebraic fraction is when a=2b

Step-by-step explanation:

You have:

$8ab^2x/4a^2b-8ab^2$

First you must to simplify:

Taking out common factor 4ab

$4ab(2bx)/4ab(a-2b)$

$2bx/a-2b$

The fraction can be written only if  the denominator is different to zero, then

a-2b$\neq$0

the excluded values are where  

a-2b=0

this expression is equal to 0 when a=2b