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satela [25.4K]
2 years ago
12

.ejjejejjwjskkwsndnnskskwmwkwkkeke

Mathematics
1 answer:
zmey [24]2 years ago
5 0

Ooh..

Mhm..

Wow!

Sounds interesting.

Nice story.

X3

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19.048

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3 years ago
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HELP PLEASE!! I DONT UNDERSTAND!!!!!!!!!! THANKS SO MUCH
8090 [49]

Hello, please consider the following.

We will multiply the numerator and denominator by

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First of all, we cannot divide by 0, right? So, we need to make sure that the denominator is different from 0.

4-\sqrt{6x} =0\sqrt{6x}=4\\\\\text{Take the square}\\\\6x=4^2=16\\\\x=\dfrac{16}{6}=\dfrac{8}{3}

We need to take any x real number different from 8/3 then and simplify the expression.

Let's do it!

\begin{aligned}\dfrac{4}{4-\sqrt{6x}}&=\dfrac{4(4+\sqrt{6x})}{(4+\sqrt{6x})(4-\sqrt{6x})}\\\\&=\dfrac{4(4+\sqrt{6x})}{(4^2-\sqrt{6x}^2)}\\\\&=\dfrac{4(4+\sqrt{6x})}{(16-6x)}\\\\&=\dfrac{2(4+\sqrt{6x})}{(8-3x)}\\\\&\large \boxed{=\dfrac{8+2\sqrt{6x}}{8-3x}}\end{aligned}

Thank you

8 0
3 years ago
Find the inverse function of <br><br> y=x^5+9
ollegr [7]

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x = \sqrt[5]{y - 9}

y^{-1}  = \sqrt[5]{x - 9}

so  inverse function of y=x^5+9 is  \sqrt[5]{x - 9}

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