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Ann [662]
3 years ago
8

In order for a button to fit through its buttonhole, the hole needs to be the size of the button's diameter. What size buttonhol

e is needed for a button with a circumference of 9.42 centimeters?
Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
8 0
The buttonhole size needed to fit the button is 3cm.

The solution is as follows:
Solve for d when C = 9.42 cm=2πr
d = 2r
r = C/2π = 9.42 / 2π
r = <span>1.49923956393
d = 2(</span>1.49923956393) = <span>2.99847912785 or <span>3cm

</span></span>

Thank you for posting your question. I hope you found what you were after. Please feel free to ask me more.

<span> </span>

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7 0
3 years ago
Find the perimeter of a quadrilateral with vertices at C (-1, 2), D (-2, -1), E (2, -2), and F (1, 1). Round your answer to the
babymother [125]

Answer:

B 12.68

Step-by-step explanation:

you will need to find the distance between each segment-

so the length of DC, CF, FE, ED

d=\sqrt{(x_{2}-x_{1})  ^{2}+(y_{2}-y_{1})  ^{2}  }

DC:

D(-2,-1) C(-1,2)

d=\sqrt{(-1--2)^{2} +(2--1)^{2} } \\d=\sqrt{1^{2}+3^{2}  } \\d=\sqrt{10} =3.16

CF:

C(-1,2) F(1,1)

d=\sqrt{(1--1)^{2} +(1-2)^{2} } \\d=\sqrt{2^{2}+-1^{2}  } \\d=\sqrt{4+1} \\d=\sqrt{x} 5=2.24

FE

F(1,1) E(2,-2)

d=\sqrt{(2-1)^{2} +(-2-1)^{2} } \\d=\sqrt{1^{2} +(-3)^{2} } \\d=\sqrt{1+9} \\d=\sqrt{10}= 3.16

ED

E(2,-2) D(-2,-1)

d=\sqrt{(-2-2)^{2} +(-1--2)^{2} } \\d=\sqrt{(-4)^{2}+1^{2}  } \\d=\sqrt{16+1} \\d=\sqrt{17}= 4.12\\

3.16+2.24+3.16+4.12= 12.68

4 0
2 years ago
Six years less than Tracey's age as an expression
likoan [24]

Answer:

T-6=X

Step-by-step explanation:

Tracey = T

X = Awnser

If we are subtracting six from Tracey's age, you would subtract six from T

since we don't know Tracey's age, it is represented by T.

Hope this Helps!

4 0
3 years ago
Given the Arithmetic series A 1 + A 2 + A 3 + A 4 A1+A2+A3+A4 14 + 18 + 22 + 26 + . . . + 86 What is the value of sum?
postnew [5]

Answer:

950

Step-by-step explanation:

The common difference is 4, so the general term can be written:

... an = 14 + 4(n -1)

The value of n for the last term is ...

... 86 = 14 + 4(n -1) . . . . . the computation for the last term, 86

... 72 = 4(n -1) . . . . . . . . . subtract 14

... 18 = n -1 . . . . . . . . . . . divide by 4

... 19 = n . . . . . . . . . . . . . add 1

Your series has 19 terms. The first term is 14 and the last is 86, so the average term is (14+86)/2 = 50. Since there are 19 terms, the sum of them is ...

... 19×50 = 950

7 0
3 years ago
by selling a cell phone for 2400rs a shopkeeper makes a profit of 25% what would be his profit percentage if it was 2040rs​
xxMikexx [17]

Answer:

6.25%

Step-by-step explanation:

We first begin by solving for the original price of the cell phone.

if 2400 = 125%

         x = 100%

By cross multplying, we get

125x = 2400 * 100

x = 240000/125

x = 1920rs

To find the profit percentage on the new sale price, we repeat another set of equations

100% = 1920

      x = 2040

1920x = 2040 * 100

x = 204000/1920

x = 106.25%

His new profit percentage is 6.25%

7 0
3 years ago
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