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Ann [662]
3 years ago
8

In order for a button to fit through its buttonhole, the hole needs to be the size of the button's diameter. What size buttonhol

e is needed for a button with a circumference of 9.42 centimeters?
Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
8 0
The buttonhole size needed to fit the button is 3cm.

The solution is as follows:
Solve for d when C = 9.42 cm=2πr
d = 2r
r = C/2π = 9.42 / 2π
r = <span>1.49923956393
d = 2(</span>1.49923956393) = <span>2.99847912785 or <span>3cm

</span></span>

Thank you for posting your question. I hope you found what you were after. Please feel free to ask me more.

<span> </span>

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Will give 25 points and brainliest answer if correct
Norma-Jean [14]
Let d be the common difference between terms in the sequence \{a_n\}_{n\ge1}. Then

a_{19}=-58
a_{20}=a_{19}+d
a_{21}=a_{19}+2d
\implies-164=-58+2d\implies d=-53

The first term in the sequence, a_1, satisfies

a_2=a_1+d
a_3=a_1+2d
a_4=a_1+3d
...
a_{19}=a_1+18d
\implies-58=a_1+18(-53)\implies a_1=896

So the explicit formula for the n-th term in the sequence is

a_n=a_1+(n-1)d\implies a_n=896-53(n-1)
5 0
4 years ago
3x-2.(x+1)=-2 denklemini sağlayan, x'in değeri kaçtır? ​
vampirchik [111]

Answer:

3x - 2(x +1) =-2

3x - 2x - 2 =-2

x = - 2 +2

x = 0

hope it helps

7 0
3 years ago
A bakery offers a sale price of $3.40 for 4 muffins. What is the price pe dozen?​
maxonik [38]

Answer:

10.2

Step-by-step explanation:

3.40 * 3 = 10.2

5 0
3 years ago
The level of CO2 emissions, f(x), in metric tons, from the town of Fairfax x years after they started recording is shown in the
Temka [501]
1) The average increase in the level of CO2 emissions per year from years 2 to 4 is:
Average=[f(4)-f(2)]/(4-2)=(29,172.15-26,460)/2=2,712.15/2=1,356.075 metric tons. The first is false.

2) The average increase in the level of CO2 emissions per year from years 6 to 8 is:
Average=[f(8)-f(6)]/(8-6)=(35,458.93-32,162.29)/2=3,296.64/2=1,648.32 metric tons. The second is false.

3) The average increase in the level of CO2 emissions per year from years 4 to 6 is:
Average=[f(6)-f(4)]/(6-4)=(32,162.29-29,172.15)/2=2,990.14/2=1,495.07 metric tons. The third is false.

4) The average increase in the level of CO2 emissions per year from years 8 to 10 is:
Average=[f(10)-f(8)]/(10-8)=(39,093.47-35,458.93)/2=3,634.54/2=1,817.27 metric tons. The fourth is true.

Answer: Fourth option: The average increase in the level of CO2 emissions per year from years 8 to 10 is 1,817.27 metric tons.
7 0
3 years ago
1/4(1/3k+9)=6 step 1- 1/3k=15 step 2- 1/3k=15 step 3- k=5 find Olgas mistake step 1 step 2 steps 3 Olga did not make a mistake
shtirl [24]

Answer:

Step 3 contains error.

Step-by-step explanation:

The given equation is :

\dfrac{1}{4}(\dfrac{1}{3}k+9)=6

Step 1.

Cross multiplying,

(\dfrac{1}{3}k+9)=24

Step 2.

Subtract 9 from both sides

\dfrac{1}{3}k+9-9=24-9\\\\\dfrac{1}{3}k=15

Step 3.

Cross multiplying

k=15\times 3\\\\k=45

So, there is an error in step 3. The correct answer should be 45.

3 0
3 years ago
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