Find the common multiples:
Multiples of 6: 6, 12, 18, 24, 30, 36, 42, 48
Multiples of 9: 9, 18, 27, 36, 45
The common multiples are 18 and 36
The first person in line to get both free would be the 18th person and then the 36th person.
So she is correct that the 36th person would get both free, but they wouldn't be the first person to do it.
In the attachement, there is what I came up with so far. I think that finding 'a' is non-trivial, if possible at all.
- the area of a circle
- the area of a circular segment
Answer:
(x + 1)² = (2x)²
(1 + 1)² = (2(1))²
2² = 2²
4 = 4
(-1 + 1)² = (2(-13))²
(-12)² = (-26)²
Not true
x = -13 satisfies neither
x+2y=6
Subtract 2y from both sides.
x=6−2y
Step-by-step explanation:
x=6-2y
8
7 - 2 + 3 = 8