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3 years ago

FInd one value of x for each

Mathematics

1 answer:

Marysya12 [62]3 years ago

7 0

Answer:

f(4) = -4 and f(-2)= 2

Step-by-step explanation:

If you trace down the graph to where the function passes the x=4 and x= -2 points, you will see it is at these values of y.

You might be interested in

A teacher student committee consisting of 4 people is to be formed from 5 teachers and 20 students. Find the probability that th

antiseptic1488 [7]

Answer:

99.96%

Step-by-step explanation:

Given the information:

5 teachers

20 students

4 people in committee

=> the are 25 people in total

Hence, the total possible outcomes of all the members in the 4 committee:

$C^{4} _{25} = 12650$

They want us to find the probability that the committee will consist of at least one student, which means that

=(Total possible outcome - committee with no student) / Total possible outcomes

So we need to find the possible outcomes of committee with no student:

= $C^{4} _{5} =5$

=> the probability that the committee will consist of at least one student.

= (12650 - 5) / 12650

= 0.9996

= 99.96%

Hope it will find you well.

5 0

3 years ago

Factor this polynomial expression.

tankabanditka [31]

Answer:

D: 3(x + 5)(x + 5)

Step-by-step explanation:

Try multiplying the last answer choice (D); the result is 3(x^2 + 10x + 25), or

3(x + 5)(x + 5).

5 0

4 years ago

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar

erma4kov [3.2K]

Answer:

$\frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}$

Step-by-step explanation:

Given

5 tuples implies that:

$n = 5$

$(h,i,j,k,m)$ implies that:

$r = 5$

Required

How many 5-tuples of integers $(h, i, j, k,m)$ are there such that $n\ge h\ge i\ge j\ge k\ge m\ge 1$

From the question, the order of the integers h, i, j, k and m does not matter. This implies that, we make use of combination to solve this problem.

Also considering that repetition is allowed: This implies that, a number can be repeated in more than 1 location

So, there are n + 4 items to make selection from

The selection becomes:

$^{n}C_r => ^{n + 4}C_5$

$^{n + 4}C_5 = \frac{(n+4)!}{(n+4-5)!5!}$

$^{n + 4}C_5 = \frac{(n+4)!}{(n-1)!5!}$

Expand the numerator

$^{n + 4}C_5 = \frac{(n+4)!(n+3)*(n+2)*(n+1)*n*(n-1)!}{(n-1)!5!}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5!}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{5*4*3*2*1}$

$^{n + 4}C_5 = \frac{(n+4)*(n+3)*(n+2)*(n+1)*n}{120}$

Solved

6 0

3 years ago

I need help! If you can help me with this I can mark you!

Alina [70]

Answer:

I think it is 82 degrees or 102 degrees depend if you pick the 10s or 100s

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Self-Check Practice Exercise 4

ryzh [129]

Answer:

A= Congruent

B= Supplementary

C= Congruent

D= Congruent

E=Supplementary

Step-by-step explanation:

5 0

4 years ago