If triangles PQR and STU are similar then PQ corresponds to ST and PR corresponds to SU. Therefore, PQ/ST=PR/SU
Considering that, PQ= 7-x, ST= 13-x, PR= x²+5 and SU= x² +20
therefore, (7-x)/(13-x)= (x²+5)/(x²+20)
cross multiplying,
7x² +140-x³+20x =13x²+65-x³-5x
combining the like terms,
6x² +15x -75=0
solving for x,
x = 5/2 or -5
Answer:
Step-by-step explanation:
Top/Bottom = 12
Sides = 15
Front/Back = 20
20 + 15 + 12 = 47
47 / 1/2 = 23.5
A(10) = <span>9(10) + 9= 90+9 =99
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Answer:
m = rise/run = 4/5.
Step-by-step explanation:
This line goes throught the "exact" grid intersections (-2, 0) and (3, 4). As we move from the first point to the second, we see that x increases by 5 (this is the 'run') and y increases by 4 (this is the 'rise'). Thus, the slope of this line is m = rise/run = 4/5.
