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grandymaker [24]
3 years ago
5

Use the equation given below to help you determine Which statement best describes how you find the net change in an your answer.

Mathematics
1 answer:
Ksivusya [100]3 years ago
7 0

Answer:

A   is the answer I go with although  Im not that sure

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Solve for X, square root 2x = square root x+5
inessss [21]
X = 5
Move the variable then cells to like terms and simplify
4 0
3 years ago
The area of a duck enclosure is 300 square feet, with 100 square feet occupied by a pond. Each duck in the enclosure needs more
SVEN [57.7K]
Answer: Choice B) x < 10

=======================================================

Explanation:

There's 300 square feet total (land+water). Of that, 100 sq ft is taken up by the pond, so we have 300-100 = 200 sq ft of dry land. 

1 duck needs more than 20 sq ft of dry land
2 ducks need more than 40 sq ft of dry land (note how 2*20 = 40)
3 ducks need more than 60 sq ft of dry land (note how 3*20 = 60)
and so on...

In general, 
x ducks need more than 20*x square feet of dry land

The max amount of dry land we have is 200 sq ft
The total amount of space the ducks take up must be less than 200 sq ft

In terms of symbols, we have
T = total space ducks take up on dry land
T = 20*x
T < 200

So we can arrive at this inequality
20*x < 200
after replacing the "T" with "20*x"

Afterward, divide both sides by 20
20*x < 200
20*x/20 < 200/20
x < 10
So we must have less than 10 ducks

If we had 10 ducks exactly, then they would take up more than 20*10 = 200 sq ft, but we only have 200 sq ft

The largest number of ducks we can have is 9 ducks.
So that's why we have a "less than" symbol instead of a "less than or equal to" symbol.
5 0
3 years ago
There is a balanced scale. On one side of the scale there are 5 spheres and 1 cube. On the other side of the scale there is 2 sp
Debora [2.8K]
The scale has two sides:
The Left Hand Side (LHS) and the Right Hand Side (RHS).
Let the weight of the sphere be represented as s
Let the weight of the cube be represented as c

Let the LHS have the 5 spheres and 1 cube, represented as = (5s + 1c)
Let the RHS have the 2 spheres and 3 cubes, represented as = (2s + 3c)

If the cube c, weighs 150 gram,  c = 150g

Since the scale is balanced, therefore the weights on the LHS would be equal to the weights on the RHS.

Therefore:        (5s + 1c) = (2s + 3c),        c = 150.
                         (5s + 1*150) = (2s + 3*150)
                         (5s + 150) = (2s + 450)    collect like terms.
                          5s  -  2s    =  450 - 150
                                    3s    =    300        Divide both sides by 3
                                       s    =   300/3
                                        s    =  100
Therefore the sphere  weighs  100 gram each.
4 0
3 years ago
PLEASE HELP, NO LINKS OR DON’T ANSWER JUST FOR POINTS OR YOU WILL BE REPORTED! WILL GIVE BRAINLIEST!!
dalvyx [7]

Answer:

9. x = 7

10. x = 12

Step-by-step explanation:

Assume the two lines are parallel.

9. The corresponding angles are congruent.

9x - 3 = 7x + 11

2x = 14

x = 7

10. The alternate interior angles are congruent.

5x - 20 = 2x + 16

3x = 36

x = 12

7 0
3 years ago
Solve for y <br> 2(y+3)=18
jeka57 [31]
Y= 6// 2(6+3)=18 because 6+ 3= 9 and 9x 2 = 18
3 0
3 years ago
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