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Anvisha [2.4K]
3 years ago
8

What do you know to be true about the values of A and B

Mathematics
2 answers:
nikklg [1K]3 years ago
4 0
I think it’s can’t be determined because we need to know at least 2 angles of a train for.
Svetllana [295]3 years ago
3 0

Answer with explanation:

There are two triangles.We will use angle sum property to get the correct Inequality.

In Triangle 1

→x° + a° + 75°=180°

→x° + a°= -75°+180°

→x° + a°= 105°

In triangle 2

→y° + b° + 60°=180°

→y°+b°=180°-60°

→y°+b°=120°

As there are four different variables ,and only two equations.So,we can't determine the value of , a and ,b.

Option D: Can't be Determined

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Answer:

Medbay

Step-by-step explanation:

6 0
3 years ago
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Clara is growing her hair out and wants it to be no longer than 15 cm but more than 11 cm. Her hair is 7 cm right now and grows
sertanlavr [38]
For this case we have the following compound inequality:
 11 <7 + 0.25t ≤ 15
 We must solve this inequality for time.
 We have then:

 For 11 <7 + 0.25t:
 
11 <7 + 0.25t
 11 - 7 <0.25t
 4 <0.25t
 4 / 0.25 <t
 16 <t

For 7 + 0.25t ≤ 15:
 7 + 0.25t ≤ 15
 0.25t ≤ 15 - 7
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 t ≤ 8 / 0.25
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 Therefore, the answer is:
 16 <t ≤ 32

 Answer:
 
16 <t ≤ 32
 
Clara has the desired length in more than 16 weeks, but up to 32 weeks.
6 0
3 years ago
If points N, U, and T are collinear, name all the segments they determine.
nexus9112 [7]
Collinear=On the same line

N-U

N-T

U-T

I believe that is what this questions is asking. :)
3 0
3 years ago
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If EF bisects CD, CG =5x-1, GD = 7x-13, EF = 6x-4, and GF =13, find EG
VARVARA [1.3K]

<em>Greetings from Brasil....</em>

As stated in the statement of the question, EF is a bisector of CD, so point G is the median point of CD, so CG = GD

5X - 1 = 7X - 13

X = 6

EF = EG + GF

6X - 4 = EG + 13      x = 6, so

6·6 - 4 = EG + 13

<h2>EG = 19</h2>

<em>(see attachment)</em>

6 0
3 years ago
SOLVE for x. log3 8 = x
Setler [38]
You are trying so solve
<span><span>3^x</span>=8</span>
and since 8 is not an integral power of x you need a calculator.
it is <span><span>ln(8)/</span><span>ln(3)</span></span>
or
<span><span><span>log(8)/</span><span>log(3)</span></span></span>
5 0
3 years ago
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