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2 years ago

-7 + 3 (-4c -3) equivalent expressions

Mathematics

1 answer:

stira [4]2 years ago

3 0

Answer:

-12c - 16

Step-by-step explanation:

$- 7 + 3( - 4c - 3) \\ = - 7 + 3 \times ( - 4c) + 3 \times ( - 3) \\ = - 7 - 12c - 9 \\ = - 16 - 12c \\ = - 12c - 16$

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2 years ago

Evaluate k = 13 helllp noww

OverLord2011 [107]

Answer:

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Step-by-step explanation:

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2 years ago

An astronaut with a mass of 80.70 kg is standing still on the surface of the Mars (Mars has an acceleration due to gravity of 3.

mariarad [96]

Answer:

Force, F = 68.93 pounds

Step-by-step explanation:

Given that,

Mass of the astronaut, m = 80.70 kg

Acceleration due to gravity on Mars, $a=3.8\ m/s^2$

The force acting on him is given by using second law of motion as :

$F=m\times a$

$F=80.70\ kg\times 3.8\ m/s^2$

F = 306.66 N

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2 years ago

SGA is doing a fundraiser to sell candles for project graduation. Small candles cost $4.00 and large candles cost $6.00. They ha

mafiozo [28]

Given:

Cost of small candles = $4.00

Cost of large candles = $6.00

They have at most 50 candles, and want to make at least $100.

To find:

The system of linear inequalities represents the situation.

Solution:

Let x be the number of small candles and y be the number of large candles.

At most 50 candles means total candles must be less than or equal to 50.

$x+y\leq 50$

Want to make at least $100. It means, the total sales must be greater than or equal to $100.

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2 years ago

(1CQ) Determine whether the series -8/5+32/25-128/125+... is convergent or divergent.

Ivan

Answer:

The series is convergent answer ⇒ (a)

Step-by-step explanation:

* The series is -8/5 + 32/25 + -128/125 + ........

- It is a geometric series with:

- first term a = -8/5 and common ratio r = 32/25 ÷ -8/5 = -4/5

* The difference between the convergent and divergent

in the geometric series is :

- If the geometric series is given by sum = a + a r + a r² + a r³ + ...

* Where a is the first term and r is the common ratio

* If |r| < 1 then the following geometric series converges to a / (1 - r).

- Where a/1 - r is the sum to infinity

* The proof is:

∵ S = a(1 - r^n)/(1 - r) ⇒ when IrI < 1 and n very large number

∴ r^n approach to zero

∴ S = a(1 - 0)/(1 - r) = a/(1 - r)

∴ S∞ = a/1 - r

* If |r| ≥ 1 then the above geometric series diverges

∵ r = -4/5

∴ IrI = 4/5

∴ IrI < 1

∴ The series is convergent

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3 years ago