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3 years ago

Which of the following are possible rational roots of the polynomial function?

Mathematics

1 answer:

gavmur [86]3 years ago

4 0

Answer: "possible" rational roots: ±1/5, ±3, ±1

Step-by-step explanation: Take plus or minus the factors of the constant divided by the factors of the leading coefficient.

In this case, the constant is 3, so the factors are 1 and 3, and the leading coefficient is 5, so the factors are 5 and 1.

1/5, 3/5, 1/1 and 3/1 are possibilities, simplify and attach the ± to each.

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Determine the value of life g(x)=4x+k is a tangent to f(x)=-x^2+8x+20

vivado [14]

Answer:

k=16

Step-by-step explanation:

So the tangent line is

$4x + k$

and it tangent to function

${x}^{2} + 8x + 20$

Since the slope of the tangent line is 4, this means the derivative of f(x) is 4 but first let find the derivative of

${x}^{2} + 8x + 20$

Use the Sum Rule,

$\frac{d}{dx} {x}^{2} + \frac{d}{dx} 8x + \frac{d}{dx} 20$

Use the Power Rule and we get

$2x + 8$

Set this equal to 4

$2x + 8 = 4$

$2x = - 4$

$x = - 2$

So at x=-2, the slope of the tangent line is 4.

Plug -2 in the orginal function, and we get

${ - 2}^{2} + 8( - 2) + 20 = 8$

So the point must pass through -2,8 with a slope of 4.

$y - 8 = 4(x + 2)$

$y - 8 = 4x + 8$

$y = 4x + 16$

So the value of k is 16.

4 0

3 years ago

102,000 with deduction of 27,549 what is net pay?

UkoKoshka [18]

102,000 - 27,549

= 74,451

5 0

4 years ago

Find the arc that is congruent to arc BF

GenaCL600 [577]

Check the picture below.

notice that the point A is the center of the circle, and thus the ∡BAF is a central angle, and the arc BF gets its angle measurement from ∡BAF, in red.

now, notice, ∡BAF has a twin vertical angle, namely ∡CAE in green, and the arc made by ∡CAE is congruent to BF.

7 0

4 years ago

What is the slope of the line y = -3x + 2? A. 2 2 B. -3 O C. -2 D. 3

Yanka [14]

Answer:

The slope of y=-3x+2 is B. -3

3 0

3 years ago

Guys I really need help with these too thanks u before!!!!

Natali5045456 [20]

Hey!!

here is your answer >>>

1) 3x - 10 > 11

let's take this as 3x - 10 = 11

3x = 21

x = 7
So, The numbers of X are always more than 7

2) 9x + 2 < 5

9x + 2 = 5

9x = 3

x = 1÷2

The numbers of X are always less than 1 ÷ 2

3) 2x + 8 < 6

2x + 8 = 6

2x = 2

x = 1

The numbers of X are less than 1

4) 4x - 3 < 12

4x - 3 = 12

4x = 15

x = 15 ÷ 4

The numbers of X are less than 15 ÷ 4

5) 2 ( 9 + x ) > 20

2 ( 9 + x ) = 20

9 + x = 10

x = 1

The numbers of X are more than 1

We can solve the rest using this

Hope my answer helps!

5 0

4 years ago