Please answer this in steps....

Darina [25.2K]

Hey there

Answer:

20% of 40 is 8 .

Step-by-step explanation:

In this question we are given a number that is 40 . And we have asked to find 20% of it .

Solution : -

$\longmapsto \qquad \: \: 20\% \times 40$

We know that ,

Percent ( % ) represent 1/100

So ,

 $\longmapsto \qquad \: \: ( 20 \times \dfrac{1}{100}) \times 40$ 

or ,

 $\longmapsto \qquad \: \: \dfrac{20}{100} \times 40$ 

Now cancelling zero :

$\longmapsto \qquad \: \: \dfrac{2 \cancel{0}}{1 \cancel{0} \cancel{0}} \times 4 \cancel{0}$

We get ,

$\longmapsto \qquad \: \: 2 \times 4$

$\longmapsto \qquad \: \: \blue{\underline{\boxed{\frak{8}}}} \quad \bigstar$

Therefore , 20% of 40 is 8 .

<h2>#Keep Learning</h2>

6 0

2 years ago

Express into partial fractions 3x³ - 5x² - 3x - 40/( x² + 4)(x - 3)

Fudgin [204]

First simplify the rational expression by dividing. The degree in the numerator has to be at least 1 less than the degree in the denominator before you can decompose into partial fractions.

(3x³ - 5x² - 3x - 40) / ((x² + 4) (x - 3)) = 3 + (4x² - 15x - 4) / ((x² + 4) (x - 3))

Now decompose the remainder term into partial fractions:

(4x² - 15x - 4) / ((x² + 4) (x - 3)) = (ax + b) / (x² + 4) + c / (x - 3)

Multiply both sides by the denominator on the left:

4x² - 15x - 4 = (ax + b) (x - 3) + c (x² + 4)

Expand the right side:

4x² - 15x - 4 = ax² + (b - 3a) x - 3b + cx² + 4c

4x² - 15x - 4 = (a + c) x² + (b - 3a) x - 3b + 4c

Then

a + c = 4

b - 3a = -15

-3b + 4c = -4

Solve this system to get

a = 5, b = 0, c = -1

We end up with

(4x² - 15x - 4) / ((x² + 4) (x - 3)) = 5x / (x² + 4) - 1 / (x - 3)

and so

(3x³ - 5x² - 3x - 40) / ((x² + 4) (x - 3))

= 3 + 5x / (x² + 4) - 1 / (x - 3)

8 0

3 years ago

A parabolic listening device is shaped such that the depth of the bowl depends on its radius and can be represented by the curve

Rus_ich [418]

Answer:

7.428 inches

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What are the coordinates of the image of C if it is reflected across the x-axis?

Svetradugi [14.3K]

Answer:

(-2, 4)

Step-by-step explanation:

~When reflecting a point of the x-axis, the x value (or first number inside the parenthesis) does not change.

The reason the x-value does not change is because you are reflecting over the x-axis, making the point go up or down. That will change the y-value but the x-value only changes if you move to the left or the right. In this case, you can see that the point's x-value is -2, so that will not change. It's current y-value however is -4. When reflecting over an axis, the number that is changing (in this case the y-value) will just be flipped from positive to negative, or vise versa. In this case, -4 will be reflected to be 4, making point C reflected over the x-axis (-2, 4).

5 0

3 years ago

Read 2 more answers

which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1

lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. $y=\sec x$

B. $y= \tan x$

C. $y= \cot x$

D. $y= \csc x$

Answer:

A. $y=\sec x$

D. $y=\csc x$

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: $y=\sec x$

We know that, the $\sec x=\frac{1}{\cos x}$

The range of $\cos x$ is from -1 to 1 given as [-1, 1]. So,

$|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the secant function as:

$\sec x\leq -1\ or\ \sec x\geq 1\\$

Therefore, the range of $y=\sec x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

Choice B: $y= \tan x$

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: $y= \cot x$

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: $y=\csc x$

We know that, the $\csc x=\frac{1}{\sin x}$

The range of $\sin x$ is from -1 to 1 given as [-1, 1]. So,

$|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

$\csc x\leq -1\ or\ \csc x\geq 1\\$

Therefore, the range of $y=\csc x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

6 0

3 years ago

Please answer this in steps....​

Please answer this in steps....