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Dafna1 [17]
3 years ago
6

Please answer this in steps....​

Mathematics
1 answer:
SOVA2 [1]3 years ago
4 0
<h2>Answer:</h2><h2>The answer is 3.14..</h2><h2>For finding it you have to divide the given numbers.</h2>

This is also a value of π (pi)

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In quadrilateral ABCD, diagonals AC and BD bisect one another: Quadrilateral ABCD is shown with diagonals AC and BD intersecting
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B. A parallelogram has congruent sides.

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Read 2 more answers
A map has a scale of 1/2 inch= 20miles quinn wants to travel an actual distance
inessss [21]

Answer:

1.75 inches or 1 3/4inches

Step-by-step explanation:

A map has a scale of ½½inch=20mles. Quinn wants to travel an actual distance of 70miles. What will the length on the map be?

70/20

=7/2

=1/2×7/2

=7/4

=1 3/4 inches

in decimal its 1.75 inches

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2 years ago
A church steeple is 30 feet tall with square cross sections. The square at the base has side 3 feet, the square at the top has s
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Answer:

Volume= 540 ft^3

Step-by-step explanation:

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3 0
3 years ago
Dividing exponents in this equation
jeka94

Answer:

18x^5y

Step-by-step explanation:

Divide 36 by 2 first : 18

since you are dividing, you subtract the exponents:

x^8 - x^3= x^5

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8 0
3 years ago
Consider the function g(x) = (x-e)^3e^-(x-e). Find all critical points and points of inflection (x, g(x)) of the function g.
Elden [556K]

Answer:

The answer is "cirtical\  points \ (x,g(x))\equiv  (e,0),(e+3,\frac{27}{e^3})"

Step-by-step explanation:

Given:

g(x) = (x-e)^3e^{-(x-e)}

Find critical points:

g(x) = (x-e)^3e^{(e-x)}

differentiate the value with respect of x:

\to g'(x)= (x-e)^3 \frac{d}{dx}e^{e-r} +e^{e-r}  \frac{d}{dx}(x-e)^3=(x-e)^2 e^{(e-x)} [-x+e+3]

critical points g'(x)=0

\to (x-e)^2 e^{(e-x)} [e+3-x]=0\\\\\to e^{(e-x)}\neq 0 \\\\\to (x-e)^2=0\\\\ \to [e+3-x]=0\\\\\to x=e\\\\\to x=e+3\\\\\to x= e,e+3

So,

The critical points of (x,g(x))\equiv  (e,0),(e+3,\frac{27}{e^3})

7 0
3 years ago
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