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Len [333]
3 years ago
8

What is the answer for number 6

Mathematics
1 answer:
liq [111]3 years ago
5 0
6)a) XL = 13 cm
b) AC = 21 cm
c) PC = 13 cm
d) Angle L = 29°
e) Angle C = 29°
f) Angle X = 122°

Hope this helps you!

Plz follow me!
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Find the area to this figure
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I think the answer is 62 cm2

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sume of angles of a triangel greater than 180 degrees when teh triange is so large that it extends to cosmological scales
Vesna [10]

In hyperbolic geometry, the angle sum of a triangle is always less than 180 degrees.

A lune is a wedge of a sphere with angle θ, represented by L(θ) in the proof.

α, β, and γ are the three angles of the triangle.

4πr²+4area[αβγ]=2L(α)+2L(β)+2L(γ)

2(2πr²+2area[αβγ])=2(L(α)+L(β)+L(γ))

2πr²+2area[αβγ]=L(α)+L(β)+L(γ)

At this point, we need to use a theorem that states that a lune whose corner angle is θ radians has an area of 2θr².

2πr²+2area[αβγ]=2αr²+2βr²+2γr²

2πr²+2area[αβγ]=2r²(α+β+γ)

π+area[αβγ]r²=α+β+γ

At this point, it is clear that the sum of the angles is equal to π plus the area[αβγ]r² (which cannot be zero).

To learn more about triangles and geometry,

brainly.com/question/2773823

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5 0
1 year ago
If you pick a card at random from a well shuffled deck, what is the probability that you get a face card or a spade?
tankabanditka [31]
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SAS is one of the answers
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Find the average value of the function on the given interval.<br> f(x)=2 ln x; [1,e]
JulijaS [17]

Answer:

f_{avg}=\frac{1}{e-1}

Step-by-step explanation:

We are given that a function

f(x)=2lnx

We have to find the average value of function on the given interval [1,e]

Average value of function on interval [a,b] is given by

\frac{1}{b-a}\int_{a}^{b}f(x)dx

Using the formula

f_{avg}=\frac{1}{e-1}\int_{1}^{e}lnx dx

By Parts integration formula

\int(uv)dx=u\int vdx-\int(\frac{du}{dx}\int vdx)dx

u=ln x and v=dx

Apply by parts integration

f_{avg}=\frac{1}{e-1}([xlnx]^{e}_{1}-\int_{1}^{e}(\frac{1}{x}\times xdx))

f_{avg}=\frac{1}{e-1}(elne-ln1-[x]^{e}_{1})

f_{avg}=\frac{1}{e-1}(e-0-e+1)=\frac{1}{e-1}

By using property lne=1,ln 1=0

f_{avg}=\frac{1}{e-1}

8 0
3 years ago
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