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-Dominant- [34]
2 years ago
9

A builder was paid £550 for the work he did. He spent 35% of the money on materials how much did the materials cost

Mathematics
1 answer:
larisa [96]2 years ago
8 0

Answer: £192.50

Step-by-step explanation:

550 x 0.35 = 192.50

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A teenager pulls a rope to the left with a force of 12 N. A child pulls on the other end of the rope to the right with a force o
alexandr402 [8]
The net force will be 3 N to the right.  

12N - 8N = 4N - 7N= -3N.  3N is the net force to the right.  
4 0
3 years ago
Find a formula for the nth term in this
stepan [7]

The formula of nth term is  = 10 - 3n

What is AP?

  • A series of numbers called an arithmetic progression or arithmetic sequence (AP) has a constant difference between the terms. Take the numbers 5, 7, 9, 11, 13, and 15 as an example. . . is a sequence of numbers having a common difference of two.
  • The n-th term of the sequence is given by:, if the beginning term of an arithmetic progression is and the common difference between succeeding members is, then
  • If the AP contains m phrases, then denotes the final term, which is given by:
  • The term "finite arithmetic progression" or "arithmetic progression" refers to a finite segment of an arithmetic progression. An arithmetic series is the total of a finite arithmetic progression.

Acc to our question-

  • For the nth term in an algebraic series
  • U(n) = a + (n - 1)d
  • the number of terms is n.
  • The first term is a.
  • d is the typical difference
  • From the preceding sequence
  • a = 7
  • d = 4 - 7 = - 3
  • The nth term's formula is
  • U(n) = 7 + (n - 1)-3
  • = 7 - 3n + 3
  • The ultimate solution is
  • = 10 - 3n

Hence,The formula of nth term is  = 10 - 3n

learn more about AP click here:

brainly.com/question/6561461

#SPJ13

3 0
1 year ago
manu took a loan of Rs 5000 for one year at 12%per annum compounded quarterly .How much he has to pay after one year.​
Shkiper50 [21]

Answer:

Amount pay after one year for compounded quarterly = Rs 5627.54

Step-by-step explanation:

Given as,

Manu took loan of Rs 5000 , So, Principal = Rs 5000

The rate of interest applied = 12% per annum compounded quarterly

The loan took for period of year = one

Now from the compounded method :

For compounded quarterly

Amount = principal (1 + \frac{Rate}{4\times 100})^{4\times Time}

Or, Amount = Rs 5000 (1+ \frac{12}{4\times 100})^{4}

Or, Amount = 5000 (\frac{103}{100})^{4}

Or, Amount = 5000 × 1.1255

∴ Amount = Rs 5627.54

Hence , The amount which Manu pay after one year at 12% per annum compounded quarterly is Rs 5627.54  Answer

5 0
3 years ago
Simplify the expression
anygoal [31]
Your answer would be -11 :) 
5 0
3 years ago
Read 2 more answers
Select the correct answer. What is the 13th term of this arithmetic sequence? 132, 135, 138, 141, … A. 168 B. 172 C. 176 D. 179
puteri [66]

Answer:

168

Step-by-step explanation:

132, 135, 138, 141, 144, 147, 150, 153, 156, 159, 162, 165, 168

5 0
3 years ago
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