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3 years ago

14

PLEASE HELP!! THIS IS MY LAST QUESTION FOR THE DAY!!!

1 answer:

lorasvet [3.4K]3 years ago

8 0

I thinksss it’s x=8 if not I’m sooo sorry

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How to solve this? Please help!

marta [7]

SinA=8/17, so arcsin(8/17) is your angle of A (around 49 degrees). 90-A is your angle for B

7 0

3 years ago

16 5x=31 what does x equal

liraira [26]

If you mean 165x = 31 , X = <span>0.19871794871
if you mean 16*5x = 31 , X = .3875
if you mean 16+5x=31 , X = 3
If you mean 16 -5x=31 , X = -3
Hope one of these is correct.</span>

6 0

3 years ago

What is the inequality?

Schach [20]

Difference in size, degree,<span> circumstances, etc.; lack of equality.</span>

3 0

3 years ago

A box with a rectangular base and open top must have a volume of 128 f t 3 . The length of the base is twice the width of base.

noname [10]

Answer:

$Width = 4ft$

$Height = 4ft$

$Length = 8ft$

Step-by-step explanation:

Given

$Volume = 128ft^3$

$L = 2W$

$Base\ Cost = \$9/ft^2$

$Sides\ Cost = \$6/ft^2$

Required

The dimension that minimizes the cost

The volume is:

$Volume = LWH$

This gives:

$128 = LWH$

Substitute $L = 2W$

$128 = 2W * WH$

$128 = 2W^2H$

Make H the subject

$H = \frac{128}{2W^2}$

$H = \frac{64}{W^2}$

The surface area is:

Area = Area of Bottom + Area of Sides

So, we have:

$A = LW + 2(WH + LH)$

The cost is:

$Cost = 9 * LW + 6 * 2(WH + LH)$

$Cost = 9 * LW + 12(WH + LH)$

$Cost = 9 * LW + 12H(W + L)$

Substitute: $H = \frac{64}{W^2}$ and $L = 2W$

$Cost =9*2W*W + 12 * \frac{64}{W^2}(W + 2W)$

$Cost =18W^2 + \frac{768}{W^2}*3W$

$Cost =18W^2 + \frac{2304}{W}$

To minimize the cost, we differentiate

$C' =2*18W + -1 * 2304W^{-2}$

Then set to 0

$2*18W + -1 * 2304W^{-2} =0$

$36W - 2304W^{-2} =0$

Rewrite as:

$36W = 2304W^{-2}$

Divide both sides by W

$36 = 2304W^{-3}$

Rewrite as:

$36 = \frac{2304}{W^3}$

Solve for $W^3$

$W^3 = \frac{2304}{36}$

$W^3 = 64$

Take cube roots

$W = 4$

Recall that:

$L = 2W$

$L = 2 * 4$

$L = 8$

$H = \frac{64}{W^2}$

$H = \frac{64}{4^2}$

$H = \frac{64}{16}$

$H = 4$

Hence, the dimension that minimizes the cost is:

$Width = 4ft$

$Height = 4ft$

$Length = 8ft$

8 0

2 years ago

Galen sold tickets for his church’s carnival for a total of $2,820. Children’s tickets cost $3 each and adult tickets cost $5 ea

Veronika [31]

Answer:

a = 195 ; c = 615

Step-by-step explanation:

So, you want to start by forming your equations...

I will use 'c' for children and 'a' for adults for my variables

3a + 30 = c

(this is because of the info that 30 more tickets than 3 times the amount of children's were sold than adult)

then for equation 2:

3c + 5a = 2820

(this is because of the prices of the tickets and the total money raised)

Then, plug in the equation for c

Your equation should look like:

3(3a + 30) + 5a = 2820

You get:

(9a +90) + 5a = 2820

Then:

14a = 2730

So:

a = 195 adult tickets sold

Plug in a, to find c:

3 (195) + 30 = c

585 + 30 = c

c = 615 children tickets sold

4 0

3 years ago