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3 years ago

PLEASE HELP!

1 answer:

5 0

To find the approximate volume that was released you will find the volume of the sphere before and after the water was released and subtract them. Use the formula for finding the volume of a sphere to do this.

Before:

V=4/3 x pi x r^3
4/3 x 3.14 x 4.5^3
V = 381.51 cubic inches

After:

V=4/3 x pi x r^3
4/3 x 3.14 x 3.6^3
V = 195.33 cubic inches

381.51 - 195.33 = 186.18 cubic inches

The answer is choice B.

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Suppose the daily customer volume at a call center has a normal distribution with mean 5,500 and standard deviation 1,000. What

lakkis [162]

Answer:

0.0665 = 6.65% probability that the call center will get between 4,800 and 5,000 calls in a day.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean 5,500 and standard deviation 1,000.

This means that $\mu = 5500, \sigma = 1000$

What is the probability that the call center will get between 4,800 and 5,000 calls in a day?

This is the p-value of Z when X = 5000 subtracted by the p-value of Z when X = 4800. So

X = 5000

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{5000 - 5500}{1000}$

$Z = -0.5$

$Z = -0.5$ has a p-value of 0.3085.

X = 4800

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4800 - 5500}{1000}$

$Z = -0.7$

$Z = -0.7$ has a p-value of 0.2420.

0.3085 - 0.2420 = 0.0665

0.0665 = 6.65% probability that the call center will get between 4,800 and 5,000 calls in a day.

4 0

3 years ago

If the exchange rate between the U.S. dollar and Mexican peso is 1:16 then that means ______.

Lera25 [3.4K]

Answer:

every U.S dollar is worth 16 Mexican pesos

7 0

4 years ago

Read 2 more answers

M_6 is (2x – 5)º and m_8 is (x + 5)º.

HACTEHA [7]

m_6 + m_8 = 180º because they form a straight line.

So, (2x-5) + (x+5) = 180

3x = 180

x = 60

So, m_115º (2•60 - 5 = 115)

Also, because the two lines are parallel m_6 = m_3 by alternate interior angles.

So, m_3 = 115º

4 0

2 years ago

(5⁴)²?????? A:5⁶ B:5⁸ C:20² D:25⁸

ArbitrLikvidat [17]

Answer:c 20

Step-by-step explanation:

4 0

3 years ago

Determine the measure of each segment then indicate whether the statements are true or false

kupik [55]

Answer:

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

A(-4, 4)

B(2, 5)

Finding the length of AB using the formula

$d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}$

$=\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}$

$=\sqrt{6^2+1}$

$=\sqrt{36+1}$

$=\sqrt{37}$

$d_{AB}\:=\sqrt{37}$

$d_{AB}=6.08$ units

Given the vertices of the segment JK

J(2, 2)

K(7, 2)

From the graph, it is clear that the length of JK = 5 units

$d_{JK}=5$ units

Given the vertices of the segment GH

G(-5, -2)

H(-2, -2)

Finding the length of GH using the formula

$d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}$

$=\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}$

$=\sqrt{3^2+0}$

$=\sqrt{3^2}$

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$d_{GH}\:=\:3$ units

Thus, from the calculations, it is clear that:

$d_{AB}=6.08$

$d_{JK}=5$

$d_{GH}\:=\:3$

Thus,

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

8 0

3 years ago