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makkiz [27]
3 years ago
7

Find a solution to the linear equation y=6x−18 by filling in the boxes with a valid value of x and y.

Mathematics
1 answer:
juin [17]3 years ago
7 0
You can choose any value for x and find the corresponding y value. So let’s assume x=1.

y=6x-18
y=6(1)-18
y=6-18
y=-12

So a correct ordered pair would be (1,-12).
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WARRIOR [948]
59 is an outlier it's not in the 70s
8 0
3 years ago
Hi, I need help.
slavikrds [6]

Answer:

B, 24 (second answer choice)

Step-by-step explanation:

4r+7s=23

r-2s=17

8r+14s=46

7r-14s=119

15r=165

r=11

11-2s=17..........by putting value of r in ii

-2s=17-11

2s= -6

s= -3

3r+3s=3*11+3(-3) you get this by putting values of r and s

       =33-9

       =24    (B)

7 0
3 years ago
Read 2 more answers
Which are solutions of the equation x2 - 16 = 0? Check all that apply.
Maurinko [17]
Last one
Because you have to substitute it
So you do X times 2 - 16 = 0
And the only X that works is the last one cause 8 X 2 = 16 and 16 -16=0
5 0
2 years ago
Find all the zeroes of the equation. x4 – 6x2 – 7x – 6 = 0
NeX [460]

Answer:

-2, 3,  -0.5 + 0.866i,   -0.5 - 0.866i.

Step-by-step explanation:

As the last term is -6 , +/- 2 , +/- 3 are possible zeroes.

Try 2:-

(2)^4 - 6(2)^2 - 7(2) - 6 = -28 so  2 is not a zero.

3:-

(3)^4 - 6(3)^2 - 7(3) - 6 = 0 so 3 is a zero.

(-2)^4 - 6(-2)^2 - 7(-2) - 6 =  0 so -2 is also a zero.

Divide the function by (x +2)(x - 3),  that is  x^2 - x - 6

gives  x^2 + x + 1

x^2 + x + 1

So we have x^2 + x + 1 = 0

x =  [-1 +/- √(1^1 - 4*1*1)] / 2

= -1 + √(-3) / 2 , - 1 - √(-3)  / 2.

= -0.5 + 0.866i, -0.5 - 0.866i

7 0
3 years ago
HELP ASAP!!!!!!!!! I gave almost half of my points plz plz plzzzzz!!!
faltersainse [42]

Answer:

heyy dejanae

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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