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NISA [10]
3 years ago
10

in a choir the ratio of men to woman is 4:7. 25% of the men prefer classical songs, and 80% of the women prefer classical songs.

What percentage of the choir prefer classical songs?
Mathematics
1 answer:
Paraphin [41]3 years ago
4 0

Answer:

60%

Step-by-step explanation:

percentage of men in the choir = (4/11) x 100 = 36.4%

percentage of women in the choir = (7/11) x 100 = 63.6%

Percentage of men in the choir that prefer classical songs =  36.4 x0.25 = 9.1%

Percentage of women in the choir that prefer classical songs = 0.8 x 63.6% = 50.9%

percentage of the choir prefer classical songs = 50.9% + 9.1% = 60%

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Example 3
chubhunter [2.5K]

Answer:

We conclude that

  • The angle ∠1 = x = 36°
  • The angle ∠2 = 4x = 4(36°) = 144°

Step-by-step explanation:

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m∠1 = 4m∠2

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Find the measure of each of the two angles.

<u>Important Points about linear pair:</u>

  • We know that when two lines meet or intersect, we get a linear pair of angles.
  • Linear pairs are basically two adjacent angles that form a line.
  • The measure of two adjacent angles forming a straight line is 180, meaning they are supplementary.

As

<1 and <2 form a linear pair

m∠1 = 4m∠2

In other words, angle 1 is 4 times the measure of angle ∠2.

Let the angle ∠1 be = x

As the angle 1 is 4 times the measure of angle ∠2, so

The angle 2 will be = 4x

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2 years ago
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Find the simple interest paid to the nearest cent for each principal, interest rate, and time.
igor_vitrenko [27]

<u>Answer:</u>

The simple interest for $152, 2.5%, 18 month is $5.7

<u>Solution:</u>

Given that, principal amount = $ 152, interest rate = 2.5 % and time period = 18 months.

Now we have to calculate the simple interest for above given values.

We know that, simple interest is given as

=\frac{\text { principal amount } \times \text { interest rate } \times \text { time period in years }}{100}

By substituting the given values, we get

\text { Simple interest }=\frac{152 \times 2.5 \times 18 \mathrm{months}}{100}

By converting 18 months to years we get,

\begin{array}{l}{=\frac{152 \times 2.5 \times \frac{18}{12}}{100}} \\\\ {=\frac{152 \times 2.5 \times \frac{3}{2}}{100}} \\\\ {=\frac{152 \times \frac{3}{2}}{40}} \\\\ {=\frac{76 \times 3}{40}=\frac{19 \times 3}{10}} \\\\ {=\frac{57}{10}=5.7}\end{array}

Hence, the simple interest is $5.7

3 0
3 years ago
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