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3 years ago

Brainliest for best answer. No stupid answers please!

Mathematics

2 answers:

SVETLANKA909090 [29]3 years ago

7 0

Answer:

Step-by-step explanation:

The standard equation is

y = mx + c

Where m is the slope and c is the y intercept

The 1st equation y = -2x + 1/4

Comparing with standard equation

the slope m = -2 and c = 1/4

The 2nd equation y = -2x - 1/4

Comparing with standard equation

the slope m = -2 and c = -1/4

To check if it as a solution

y = -2x + 1/4.......(1)

y = -2x - 1/4........(2)

Substracting (2) from (1)

y - y = -2x + 2x + 1/4 + 1/4

No solution since both x and y were eliminated

gladu [14]3 years ago

3 0

Answer:

They both have the same slope.

They have different y- intercepts.

They have no solution.

Please let me know, if I am right or wrong. I try my best to give correct answers

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Which values in this data set are outliers?

Stels [109]

The median value is 79.36
M+M/2=119.04...
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So I think outliers are 120 and 35

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3 years ago

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The path of two bumper cars can be represented by the functions x + y = –5 and y = x2 – x – 6. At which locations will the bumpe

Alex Ar [27]

Equaling the equations, it is found that the cars hit each other at: (-1,-4) and (1,-6).

---------------------------------

For the first car, we have that:

$x + y = -5$

Thus:

$y_1 = -5 - x$

---------------------------------

For the second car:

$y_2 = x^2 - x - 6$

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They meet at the the values of x for which:

$y_1 = y_2$

Thus:

$-5 - x = x^2 - x - 6$

$x^2 - 1 = 0$

$x^2 = 1$

$x = \pm \sqrt{1}$

$x = \pm 1$

When $x = 1$ , they meet at $y = -5 - 1 = -6$
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Thus (-1,-4) and (1,-6).

A similar problem is given at brainly.com/question/13308311

3 0

3 years ago

Q5. The ratio of boys to girls in a group is 7:1. If there are 48 more boys

Airida [17]

Answer:

There are 8 girls

Step-by-step explanation:

We see that right now there are 6 more boys than girls and if there were 2 girls there would be 14 boys meaning there would be 12 more boys than girls if you continue in this pattern you would get-

7:1= 6 more boys 35:5=30 more boys

14:2= 12 more boys 42:6= 36 more boys

21:3=18 more boys 49:7= 42 more boys

28:4= 24 more boys 56:8= 48 more

This shows us that if there are 8 girls in group there are 56 boys meaning there are 48 more boys than girls if the group had 8 girls

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3 years ago

Estimate the size of a crowd walking in a charity fundraising march that occupies a rectangular space with dimensions of 10 feet

jolli1 [7]

Answer:

4000 is size of a crowd walking in a charity fundraising March.

Step-by-step explanation:

Given:

Dimensions of rectangular space 10 feet by 12000 feet

So we can say that,

Length = 1200 ft

Width = 10 ft

Now we will calculate the area of rectangular space which is given by

Hence Area will be = $length\times width= 10\ ft \times 1200 \ ft= 12000 \ ft^2$

Now we know that 40 people occupy a rectangle measuring 10 feet by 12 feet.

Length = 12 ft

Width = 10 ft

Area = $length\times width= 10\ ft \times 12 \ ft= 120 \ ft^2$

It says that 40 people are occupied in 120 $ft^2$

So how many people will be there in 12000 $ft^2$

By using unitary method we get,

Number of people = $\frac{40\times 12000 \ ft^2}{120 \ ft^2} = 4000 \ peoples$

Size of a crowd walking in a charity fundraising March is 4000.

8 0

4 years ago

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0.955 to the nearest tenths place

tensa zangetsu [6.8K]

Your answer is 1.0 good luck hope i helped u ☺

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3 years ago

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