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3 years ago

Which describes the effect of the transformations on the graph of ƒ(x) = x2 when changed to ƒ(x) = 5(x + 4)2 + 6?

Mathematics

1 answer:

marusya05 [52]3 years ago

8 0

Strerch by factor of 5 on y-axis.

Shift by 4 to the left on x-axis.

Shift by 6 up the y-axis.

Hope this helps.

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Me.Webster is buying carpet for n exercise room in his basement. The room will have an area of 230 square ft. The width of the r

Kipish [7]

Area is length times width. Because dividing is the exact opposite of multiplying, we can divide for the answer.

230 divided by 12.5 equals 18.4

230 ÷ 12.5 = 18.4

4 0

3 years ago

A house today costs

GenaCL600 [577]

Answer:

$585,000. 95% of $300,000 = $285,000. $300,000 + $285,000 = $585,000. hope this helps

Step-by-step explanation:

- Zombie

8 0

3 years ago

José, vecino de mi calle, me ofrece $3840 por mi computadora, con lo que ganaría el 28% del costo. Siete días después se la vend

borishaifa [10]

Ganaste 25% del precio original.

3 0

4 years ago

a major metroplitan newspaper selected a simple random sample of 1,600 readers from their list of 100,000 subscribers. they aske

Arisa [49]

Answer:

The 99% confidence interval for the proportion of readers who would like more coverage of local news is (0.3685, 0.4315).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 1600, \pi = 0.4$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a pvalue of $1 - \frac{0.01}{2} = 0.995$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 - 2.575\sqrt{\frac{0.4*0.6}{1600}} = 0.3685$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 + 2.575\sqrt{\frac{0.4*0.6}{1600}} = 0.4315$

The 99% confidence interval for the proportion of readers who would like more coverage of local news is (0.3685, 0.4315).

7 0

3 years ago

Solve the sequence:0,5,12,23,34____

MrRissso [65]

Step-by-step explanation:

the answer is 49

I may not be correct

4 0

2 years ago