Question

Estimate the size of a crowd walking in a charity fundraising march that occupies a rectangular space with dimensions of 10 feet by 1,200 feet (to the nearest whole number). Assume that 40 people occupy a rectangle measuring 10 feet by 12 feet.

Answer 1

Answer:

4000 is size of a crowd walking in a charity fundraising March.

Step-by-step explanation:

Given:

Dimensions of rectangular space 10 feet by 12000 feet

So we can say that,

Length = 1200 ft

Width = 10 ft

Now we will calculate the area of rectangular space which is given by

Hence Area will be = $length\times width= 10\ ft \times 1200 \ ft= 12000 \ ft^2$

Now we know that 40 people occupy a rectangle measuring 10 feet by 12 feet.

Length = 12 ft

Width = 10 ft

Area = $length\times width= 10\ ft \times 12 \ ft= 120 \ ft^2$

It says that 40 people are occupied in 120 $ft^2$

So how many people will be there in 12000 $ft^2$

By using unitary method we get,

Number of people = $\frac{40\times 12000 \ ft^2}{120 \ ft^2} = 4000 \ peoples$

Size of a crowd walking in a charity fundraising March is 4000.

Answer 2

Answer:

4,000 people

Step-by-step explanation:

49 people occupy 120 ft^2

Dimensions of crowd: 10×1,200=12,000

120 ft^2/40 people = 12,000 ft^2/x people

X=4,000