3 years ago

Which equation represents the general from circle w

Mathematics

1 answer:

aev [14]3 years ago

8 0

$d. \: {x}^{2} + {y}^{2} - 4x - 6y - 3 = 0 \\ \\ x = 2 + \infty \sqrt{(y - 7)(y + 1)} 2 - \infty \sqrt{(y - 7)(y + 1)}$

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from the line y=2x-10 find the equation of the line that is perpendicular to this line and goes through the point (9,-5)

creativ13 [48]

2 is the slope so the slope perpendicular to that is -1/2 (negative reciprocal)
-5=-1/2(9) 9*-1/2=-4.5 and -4.5 - 0.5 = -5 so the equation for the line is y=-1/2x -0.5

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3 years ago

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kipiarov [429]

Answer:

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I NEED HELP!!!!!!!! WHAT IS THIS!? I'll mark BRAINLIEST if anyone can answer correctly!

VikaD [51]

So the rule with dividing exponents of the same base is to just subtract the exponents. Using this rule, we solve the equation as such:

$\frac{p^{-4}q^5r^6}{p^{-3}q^1r^{-2}}=p^{-4-(-3)}q^{5-1}r^{6-(-2)}=p^{-1}q^4r^8$

Next, assuming that you only want positive exponents, to get from a negative exponent to a positive one the rule is $x^{-m}=\frac{1}{x^m}$ . Using this rule, your final answer is going to be $\frac{q^4r^8}{p^1}$