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Salsk061 [2.6K]
3 years ago
15

Consider a steel ball floating on the surface of mercury in a half-filled container. What happens when the rest of the container

is filled with water
Mathematics
1 answer:
Helen [10]3 years ago
8 0

Answer

The steel ball will be caught up in between the mercury and water medium.

Step-by-step explanation:

  • Mercury with a density of 13546 kg/m^3
  • water with a density of 1000 kg/m^3
  • Steel with a density of 8050 kg/m^3

From the factual density of both substances given above ,it shows that mercury is more heavier than water. In that case mercury will be at the lower layer when mixed with water.

The steel ball will be caught in between both mixtures as the density of  steel is 8050 kg/m^3.Which  is more than Water but less than Mercury.

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puteri [66]
You’re right, it’s just 100/25.
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during the 1998-1998 little league season, the tigers played 40. they won 18 more games than they lost.how many games did they w
Makovka662 [10]
40-18= 22
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Find the first term of the following geometric sequence ----,42,126,378,1,134
sergey [27]
Since it is a geometric sequence each term will be a specific multiple of the term preceding it, called the common ratio...

126/42=378/126=1134/378=3

The sequence is a(n)=a(3)^(n-1) and we know the second term is 42 so:

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kupik [55]

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The sum of twice a number and 15 is grater the 3
NNADVOKAT [17]

Answer:

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