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GalinKa [24]
3 years ago
15

An animal shelter spends $5.50 per day to care for each cat and $8.00 per day to care for each dog. Angel noticed that the shelt

er spent $54.00 caring for cats and dogs on Monday. Angel found a record showing that there were a total of 8 cats and dogs on monday. How many cats were at the shelter on Monday?
Mathematics
1 answer:
BartSMP [9]3 years ago
3 0

Answer: there were 4 cats at the shelter on Monday.

Step-by-step explanation:

Let x represent the number of cats at the shelter on Monday.

Let y represent the number of dogs at the shelter on Monday.

Angel found a record showing that there were a total of 8 cats and dogs on monday. This means that

x + y = 8

The animal shelter spends $5.50 per day to care for each cat and $8.00 per day to care for each dog. Angel noticed that the shelter spent $54.00 caring for cats and dogs on Monday. This means that

5.5x + 8y = 54- - - - - - - - - - - - -1

Substituting x = 8 - y into equation 1, it becomes

5.5(8 - y) + 8y = 54

44 - 5.5y + 8y = 54

- 5.5y + 8y = 54 - 44

2.5y = 10

y = 10/2.5

y = 4

x = 8 - y = 8 - 4

x = 4

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Forty-seven percent of fish in a river are catfish. Imagine scooping out a simple random sample of 25 fish from the river and ob
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Question options:

The standard deviation is 0.0998. The 10% condition is not met because there are less than 250 fish in the river.

The standard deviation is 0.0998. The 10% condition is met because it is very likely there are more than 250 fish in the river.

The standard deviation is 0.9002. The 10% condition is met because it is very likely there are more than 250 fish in the river.

The standard deviation is 0.9002. The 10% condition is not met because there are less than 250 fish in the river.

We are unable to determine the standard deviation because we do not know the sample mean. The 10% condition is met because it is very likely there are more than 250 fish in the river

Answer:

The standard deviation is 0.0998. The 10% condition is met because it is very likely there are more than 250 fish in the river

Explanation:

Formula to calculate standard deviation = √p(1-p)/n

Given p= population proportion

n= sample size

From the question,

We are given p(population proportion of catfish in the river)= 0.47

n(sample size of fish collected from river) = 25

The standard deviation using the formula above = √0.47(1-0.47)/25

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The 10% condition demands that a sample size be not less than 10% of the population

To check if the 10% condition was met, we know that a river will likely have up to 250 fish in it and so,

10% of 250= 0.10×250=25 fish

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