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Elodia [21]
3 years ago
6

What type of line is perpendicular to a linear equation that is not a function

Mathematics
1 answer:
enyata [817]3 years ago
6 0

Answer:

Determine whether lines are parallel or perpendicular given their equations; Find equations of . We can begin by using point-slope form of an equation for a line. No. For two perpendicular linear functions, the product of their slopes is –1.

Step-by-step explanation:

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Jeremiah always rides his bike to and from work the total length of the trip to and from work is 14.6 kilometers last month Jere
dezoksy [38]

Answer:

As per the given statement: Jeremiah always rides his bike to and from work the total length of the trip to and from work is 14.6 kilometers last month.

⇒\text{Total length of the trip to and fro from work last month} = 14.6 km

Also, it is given that Jeremiah worked 18 days.

then;

\text{Total distance he ride his bike} = 14.6 \times 18 = \frac{146}{10} \times 18 = \frac{146 \times 18}{10} = \frac{2628}{10}

Simplify:

\text{Total distance he ride his bike} = 262.8 km

Therefore, 262.8 km did he rode his bike to and from work last month

8 0
3 years ago
What is the answer of this pls help?
Juliette [100K]

Answer:

  1. \lim_{n \to \infty} a_n  \lim_{n \to \infty} a_n  \lim_{n \to \infty} a_n  \lim_{n \to \infty} a_n

Step-by-step explanation:

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2 years ago
Two line segments intersect to form an angle that has a measure of 50.7°. What is the measure, in
Pani-rosa [81]
You should adda photo it would be more
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2 years ago
the length of time it takes to find a parking spot in the library parking lot follows a normal distribution with a man of 3.5 mi
Genrish500 [490]

Answer:

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4 0
2 years ago
The position of an object at time t is given by s(t) = 6 - 14t. Find the instantaneous velocity at t = 6 by finding the derivati
nikdorinn [45]

Answer:

<em>It results -14 in either way</em>

Step-by-step explanation:

<u>Velocity As A Rate Of Change </u>

The velocity of an object can be computed as the rate of change of its displacement (or position taken as a vector) over time. If we compute it as a derivative, it's called instantaneous velocity, and if computed as the slope of the function (difference quotient) at a certain point it's the average velocity

The position of the object as a function of time is

\displaystyle s(t)=6-14t

Computing the derivative

\displaystyle s'(t)=-14

We can see it's a constant value. If we use the slope or rate of change:

\displaystyle v=\frac{s_2-s_1}{t_2-t_1}

Now let's fix two values for time  

\displaystyle t_1=5\ sec,\ t_2=8\ sec

and compute the corresponding positions, by using the given function

\displaystyle s_1=6-14(5)=-64

\displaystyle s_2=6-14(8)=-106

Now we compute the average velocity

\displaystyle v=\frac{-106-(-64)}{8-5}

\displaystyle v=\frac{-106+64}{3}=\frac{-42}{3}

\displaystyle v=-14

We get the very same result in both ways to compute v. It happens because the position is related with time as a linear function, it's called a constant velocity motion.

7 0
3 years ago
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