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3 years ago

Find the length of a line segment CD with endpoint C at (-3,1) and endpoint D at (5,6)

1 answer:

8 0

I believe your length would be 8, because -3 to get to 0 is 3 then after that you still have 5 so you add them and get 8

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one each day dariene write in her personal diary and records whether the sun isshining or not when she looked back tough her dia

Svetradugi [14.3K]

Im guessing ten or some sort of factor of ten

7 0

3 years ago

Read 2 more answers

11+8q=3q-19 I need help please idk the answer

iren2701 [21]

Answer:

-6

Step-by-step explanation:

1) combine all like terms

(bring 3q to the left and 11 to the right so you can combine the like terms)

(doing that will make 3q negative and 11 negative since your moving them so their sign changes as well)

8q-3q=-19-11

5q=-30

Q=-6

Hope this helps

4 0

3 years ago

Question:

aivan3 [116]

Answer:

part A) The scale factor of the sides (small to large) is 1/2

part B) Te ratio of the areas (small to large) is 1/4

part C) see the explanation

Step-by-step explanation:

Part A) Determine the scale factor of the sides (small to large).

we know that

The dilation is a non rigid transformation that produce similar figures

If two figures are similar, then the ratio of its corresponding sides is proportional

Let

z ----> the scale factor

$\frac{CB}{C'B'}=\frac{CD}{C'D'}=\frac{BD}{B'D'}$

The scale factor is equal to

$z=\frac{CB}{C'B'}$

substitute

$z=\frac{4}{8}$

simplify

$z=\frac{1}{2}$

Part B) What is the ratio of the areas (small to large)?

Area of the small triangle

$A=\frac{1}{2}(2)(4)=4\ units^2$

Area of the large triangle

$A=\frac{1}{2}(4)(8)=16\ units^2$

ratio of the areas (small to large)

$ratio=\frac{4}{16}=\frac{1}{4}$

Part C) Write a generalization about the ratio of the sides and the ratio of the areas of similar figures

In similar figures the ratio of its corresponding sides is proportional and this ratio is called the scale factor

In similar figures the ratio of its areas is equal to the scale factor squared

4 0

3 years ago

What is the constant of vanation, of the line y = for through (3.18) and (5,30)?

Naily [24]

the constant of variation or namely its slope will be

$\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{18})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{30}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{30-18}{5-3}\implies \cfrac{12}{2}\implies 6$

8 0

3 years ago

A dog has a 25 ft leash attached to a corner where a garage and fence meet. When the dog pulls the leash tight and walks from th

dalvyx [7]

Answer: $170^{\circ}$

Step-by-step explanation:

Given

The dog has a 25 ft leash

Arc length is 74.3 ft

Arc length is given by

$l=\dfrac{\theta }{360^{\circ}}\times 2\pi r$

here, r=25 ft

l=74.3 ft

Put the values

$\Rightarrow 74.3=\dfrac{\theta }{360^{\circ}}\times 2\pi \times 25\\\\\Rightarrow \theta =170.2^{\circ} \approx 170^{\circ}$

The measure of the angle is $170^{\circ}$

7 0

2 years ago