Question

D(-3,5)

Answer 1

Answer:

$4\sqrt{37} units$ is the perimeter of square ABCD.

Step-by-step explanation:

Coordinates of square ABCD:

A = (3,4), B = (2,-2), C = (-4-1) , D = (-3,5)

Distance formula: $(x_1,y_1),(x_2,y_2)$

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Distance of AB: A = (3,4), B = (2,-2)

$AB=\sqrt{(2-3)^2+(-2-4)^2}$

$AB=\sqrt{(-1)^2+(-6)^2}=\sqrt{37} units$

Given that the ABCD is square, then:

AB = BC = CD = DA

Perimeter of the square ABC = AB +BC + CD + DA

$AB+ AB+ AB+ AB= 4AB=4\sqrt{37} units$

$4\sqrt{37} units$ is the perimeter of square ABCD.