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Zarrin [17]
3 years ago
12

Plz pzl plz help me and give 30

Mathematics
2 answers:
Nataly_w [17]3 years ago
5 0
X=6

Hope this helps!! <3
Mrrafil [7]3 years ago
4 0

Answer:

x=6

Step-by-step explanation:

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Pachacha [2.7K]
5 is the mean of variable a I might be wrong

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2 years ago
The sum area please.
Ann [662]

Answer:

4xy+24y^2−7x−38y−7

Step-by-step explanation:

(-7+4y) (6y+x+1)

-7*6y= -42y

-7*x= -7x

-7*1= -7

4y*6y= 24y²

4y*x= 4yx

4x*1= 4y

Add them up

3 0
3 years ago
Josie buys a necklace for $24 which is 80% off. How much was the full price of the necklace
Sedbober [7]

Answer:

4.8

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Please help!
agasfer [191]
Ok im not sure the answer yet so ima work on it at the same time while im explaining it. (The answer will probably be near the end)

We can use the elimination method to eliminate y out. To do that we multiply the first equation by 3.

6x+3y=-12

Now just subtract it from the other equation.

6x+3y=-12
5x+3y=-6

***x=-6***

Usually after doing the elimination method you will have to solve for x but in this case its already solved for you. If you want to find y now you just take the first equation and fill x with -6 and solve for y.

2(-6)+y=-4
-12+y=-4
y=8

Brainliest my answer if it helps you out?
4 0
3 years ago
Read 2 more answers
A box is being created out of a 15 inch by 10 inch sheet of metal. Equal-sized squares are cutout of the corners, then the sides
ivolga24 [154]

Answer:

Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box  has largest volume.

Step-by-step explanation:

Given that,

A box is being created out of a 15 inches by 10 inches sheet of metal.

The length of the one side of the squares which are cut out of the each corners of the metal sheet be x.

The length of the metal box be = (15-2x) inches.

The width of the metal box be =(10-2x) inches

The height of the metal box be =x inches

Then, the volume of the metal box= length×width×height

                                                         =(15-2x)(10-2x)x cubic inches

                                                         =(150x-50x²+4x³) cubic inches

∴ V= 4x³-50x²+15x

Differentiating with respect to x

V'=12x²-100x+15

Again differentiating with respect to x

V''=24x-100

For maximum or minimum value, V'=0

12x²-100x+15=0

Apply quadratic formula x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}, here a=12, b= -100 and c=15

x=\frac{-(-100)\pm\sqrt{(-100)^2-4.12.15}}{2.12}

\Rightarrow x=\frac{100\pm\sqrt{9280}}{2.12}

\Rightarrow x=0.1528,8.18

For x= 8.18, The value of (15-2x) and (10-2x) will negative.

∴x=0.1528 .

Now, V''|_{x=0.1528}=24(0.1528)-100

∴At x=0.1528 inch, the volume of the metal box will be maximum.

Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box  has largest volume.

4 0
3 years ago
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