All categories

3 years ago

I need help on this stuck on it

Mathematics

1 answer:

rewona [7]3 years ago

8 0

Answer:

5=148 and 8=32

Step-by-step explanation:

For this equation we know since the lines are parelle that they will produce the same angle degrees.

so 2,4,6,and 8 are all 32

if we subtract 180 (the dregree of a stright line) from 32 we get 148

so 148 is for 1,3,5, and 7

You might be interested in

2/3 of the cost of the sweater is $18

blagie [28]

The total of the sweater is $27.
Divide 18/1 by 2/3. You would get 27. Which means 1/3 of the sweater is $9.
And 2/3 would be $18.

3 0

3 years ago

Logarithms and exponentials are?

Aneli [31]

Answer:

Logarithms are the "opposite" of exponentials, just as subtraction is the opposite of addition and division is the opposite of multiplication. Logs "undo" exponentials. Technically speaking, logs are the inverses of exponentials. On the left-hand side above is the exponential statement "y = bx

Step-by-step explanation:

3 0

3 years ago

Can you help me write this in standard form <br><img src="https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B3%7D%7B2%7D%20x%20-%20%

Karo-lina-s [1.5K]

I think it’s 15x-10y=2

3 0

3 years ago

Many elementary school students in a school district currently have ear infections. A random sample of children in two different

Marta_Voda [28]

Answer:

Step-by-step explanation:

The summary of the given data includes;

sample size for the first school $n_1$ = 42

sample size for the second school $n_2$ = 34

so 16 out of 42 i.e $x_1$ = 16 and 18 out of 34 i.e $x_2$ = 18 have ear infection.

the proportion of students with ear infection Is as follows:

$\hat p_1 = \dfrac{16}{42}$ = 0.38095

$\hat p_2 = \dfrac{18}{34}$ = 0.5294

Since this is a two tailed test , the null and the alternative hypothesis can be computed as :

$H_0 :p_1 -p_2 = 0 \\ \\ H_1 : p_1 - p_2 \neq 0$

level of significance ∝ = 0.05,

Using the table of standard normal distribution, the value of z that corresponds to the two-tailed probability 0.05 is 1.96. Thus, we will reject the null hypothesis if the value of the test statistics is less than -1.96 or more than 1.96.

The test statistics for the difference in proportion can be achieved by using a pooled sample proportion.

$\bar p = \dfrac{x_1 +x_2}{n_1 +n_2}$

$\bar p = \dfrac{16 +18}{42 +34}$

$\bar p = \dfrac{34}{76}$

$\bar p = 0.447368$

$\bar p + \bar q = 1 \\ \\ \bar q = 1 -\bar p \\ \\\bar q = 1 - 0.447368 \\ \\\bar q = 0.552632$

The pooled standard error can be computed by using the formula:

$S.E = \sqrt{ \dfrac{ \bar p \bar q}{ n_1} + \dfrac{\bar p \bar p}{n_2} }$

$S.E = \sqrt{ \dfrac{ 0.447368 * 0.552632}{ 42} + \dfrac{ 0.447368 * 0.447368}{34} }$

$S.E = \sqrt{ \dfrac{ 0.2472298726}{ 42} + \dfrac{ 0.2001381274}{34} }$

$S.E = \sqrt{ 0.01177284105}$

$S.E = 0.1085$

The test statistics is ;

$z = \dfrac{\hat p_1 - \hat p_2}{S.E}$

$z = \dfrac{0.38095- 0.5294}{0.1085}$

$z = \dfrac{-0.14845}{0.1085}$

z = - 1.368

Decision Rule: Since the test statistics is greater than the rejection region - 1.96 , we fail to reject the null hypothesis.

Conclusion: There is insufficient evidence to support the claim that a difference exists between the proportions of students who have ear infections at the two schools

5 0

3 years ago

tickets to a concert cost $15 online and $25 at the door. one hundred more people bought their tickets at the door than online.

DochEvi [55]

25X100= 2,500 at the door
2,500-20,500 = 18,000 lift
18,000/15 =1,200 people on line

3 0

3 years ago

Read 2 more answers