1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Natasha2012 [34]
3 years ago
9

Use-Cases are scenarios that describe

Computers and Technology
1 answer:
Misha Larkins [42]3 years ago
6 0

Answer:  Use- cases are scenarios that describe how software is to be used in a given situation.

Explanation:

Use-cases has multiple path that can be used by the users at one time and it basically described how software can be used in a given situation. A use case scenarios is a single path by the use-case. There are two types of use cases:

system use cases and business use cases. Use cases are basically used in a system to identifies and analysis of system software requirements.

You might be interested in
Complete the sentence.
KatRina [158]

Answer:

tCP

Explanation:

6 0
3 years ago
What programming language is used for Arduinos?
Helen [10]

For Arduinos, C++ wrappers around C are used. The goal is to hide the details with setting up and using the AVR, therefore, it's a pretty simple program.

Answer: C++

(P.S. copy and paste your question into google or safari and click on the link to reddit because there's a lot of good info about this there)

+ = <3

4 0
3 years ago
Read 2 more answers
A database at a college is required to support the following requirements. Complete the information-level design for this set of
Maslowich

Answer:

Explanation:

check the attached files below for answers to your question, thanks.

6 0
3 years ago
1)
spayn [35]

Answer:

1)

for(i = 0; i < NUM_VALS; ++i) {

  if(userValues[i] == matchValue) {

     numMatches++;  }    }

2)  

for (i = 0; i < NUM_GUESSES; i++) {

      scanf("%d", &userGuesses[i]);   }

  for (i = 0; i < NUM_GUESSES; ++i) {

         printf("%d ", userGuesses[i]);    }

3)

sumExtra = 0;

for (i = 0; i < NUM_VALS; ++i){

     if (testGrades[i] > 100){  

        sumExtra = testGrades[i] - 100 + sumExtra;    }       }

4)

for (i = 0; i < NUM_VALS; ++i) {

    if (i<(NUM_VALS-1))  

   printf( "%d,", hourlyTemp[i]);

    else  

    printf("%d",hourlyTemp[i]); }      

Explanation:

1) This loop works as follows:

1st iteration:

i = 0

As i= 0 and NUM_VALS = 4 This means for condition i<NUM_VALS  is true so the body of loop executes

if(userValues[i] == matchValue) condition checks if element at i-th index position of userValues[] array is equal to the value of matchValue variable. As matchValue = 2 and i = 0 So the statement becomes:

userValues[0] == 2

2 == 2

As the value at 0th index (1st element) of userValues is 2 so the above condition is true and the value of numMatches is incremented to 1. So numMatches = 1

Now value of i is incremented to 1 so i=1

2nd iteration:

i = 1

As i= 1 and NUM_VALS = 4 This means for condition i<NUM_VALS  is true so the body of loop executes

if(userValues[i] == matchValue) condition checks if element at i-th index position of userValues[] array is equal to the value of matchValue variable. As matchValue = 2 and i = 1 So the statement becomes:

userValues[1] == 2

2 == 2

As the value at 1st index (2nd element) of userValues is 2 so the above condition is true and the value of numMatches is incremented to 1. So numMatches = 2

Now value of i is incremented to 1 so i=2

The same procedure continues at each iteration.

The last iteration is shown below:

5th iteration:

i = 4

As i= 4 and NUM_VALS = 4 This means for condition i<NUM_VALS  is false so the loop breaks

Next the statement: printf("matchValue: %d, numMatches: %d\n", matchValue, numMatches);  executes which displays the value of

numMatches = 3

2)

The first loop works as follows:

At first iteration:

i = 0

i<NUM_GUESSES is true as NUM_GUESSES = 3 and i= 0 so 0<3

So the body of loop executes which reads the element at ith index (0-th) index i.e. 1st element of userGuesses array. Then value of i is incremented to i and i = 1.

At each iteration each element at i-th index is read using scanf such as element at userGuesses[0], userGuesses[1], userGuesses[2]. The loop stops at i=4 as i<NUM_GUESSES evaluates to false.

The second loop works as follows:

At first iteration:

i = 0

i<NUM_GUESSES is true as NUM_GUESSES = 3 and i= 0 so 0<3

So the body of loop executes which prints the element at ith index (0-th) index i.e. 1st element of userGuesses array. Then value of i is incremented to i and i = 1.

At each iteration, each element at i-th index is printed on output screen using printf such as element at userGuesses[0], userGuesses[1], userGuesses[2] is displayed. The loop stops at i=4 as i<NUM_GUESSES evaluates to false.

So if user enters enters 9 5 2, then the output is 9 5 2

3)

The loop works as follows:

At first iteration:

i=0

i<NUM_VALS is true as NUM_VALS = 4 so 0<4. Hence the loop body executes.

if (testGrades[i] > 100 checks if the element at i-th index of testGrades array is greater than 100. As i=0 so this statement becomes:

if (testGrades[0] > 100

As testGrades[0] = 101 so this condition evaluates to true as 101>100

So the statement sumExtra = testGrades[i] - 100 + sumExtra; executes which becomes:

sumExtra = testGrades[0] - 100 + sumExtra

As sumExtra = 0

testGrades[0] = 101

So

sumExtra = 101 - 100 + 0

sumExtra = 1

The same procedure is done at each iteration until the loop breaks. The output is:

sumExtra = 8

4)

The loop works as follows:

At first iteration

i=0

i < NUM_VALS is true as  NUM_VALS = 4 so 0<4 Hence loop body executes.

if (i<(NUM_VALS-1))   checks if i is less than NUM_VALS-1 which is 4-1=3

It is also true as 0<3 Hence the statement in body of i executes

printf( "%d,", hourlyTemp[i]) statement prints the element at i-th index i.e. at 0-th index of hourlyTemp array with a comma (,) in the end. As hourlyTemp[0] = 90; So 90, is printed.

When the above IF condition evaluates to false i.e. when i = 3 then else part executes which prints the hourlyTemp[3] = 95 without comma.

Same procedure happens at each iteration unless value of i exceeds NUM_VAL.

The output is:

90, 92, 94, 95

The programs along with their output are attached.

4 0
4 years ago
arjun ahs joined a work teams that assembles products what is the best way for arjun to build the teams trust in him
kvv77 [185]
I’m just answering to get points
3 0
3 years ago
Other questions:
  • Bob's Assembly is a hardware manufacturer. It specializes in builders' hardware for doors, cabinets, windows, and bathrooms. Bob
    10·1 answer
  • Which of the following should businesses and organizations do to promote a safe work environment?
    6·1 answer
  • Which protocol is the data transmission standard for the Internet, responsible for sending information from one computer to anot
    14·1 answer
  • We need ____ pointers to build a linked list.
    6·1 answer
  • Want summmmmmmm bec i do lol
    9·1 answer
  • Analyze the following recursive method and indicate which of the following will be true.
    7·1 answer
  • Convert 3BA.25 (base 14) to base 6 ? Show all arithmetic in decimal
    5·1 answer
  • Final one bit l y links are a virus that will corrupt your files do not go on it
    15·2 answers
  • Why is it important to follow a consistent naming convention for variables?
    7·1 answer
  • When a ____________ file is opened, it appears full-screen, in slideshow mode, rather than in edit mode.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!