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vagabundo [1.1K]
1 year ago
6

When a ____________ file is opened, it appears full-screen, in slideshow mode, rather than in edit mode.

Computers and Technology
1 answer:
GrogVix [38]1 year ago
6 0

Answer:

pptx

Explanation:

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Add my sna-p dkarpik58?...
BARSIC [14]

<u><em>This is for answers not snap</em></u>

7 0
3 years ago
Which tool is used to view stars in galaxies far from the Milky Way?
Rom4ik [11]
<span>The tool iused to view stars in galaxies far from the Milky Way is the B. Hubble Space Telescope. This telescope is one of the largest telescopes to be launched in space, and has contributed a vast amount of discoveries and data that are valuable in astronomical research. The telescope is able to capture image intense high-resolution images, capturing entities from large distances.</span>
7 0
2 years ago
Programs for embedded devices are often written in assembly language. Some embedded processors have limited instructions, like M
oksano4ka [1.4K]

Answer:

#include <iostream>

using namespace std;

int main()

{

   char address[2];

   int tag, firstBit, secondBit, setNumber;

   int cache[4][2]={{1,5}, {2,4}, {3,2}, {6,0}};

   cout << "Enter the address as hex(in small letters: "<

   cin >> address;

   for (int i < 0; i < 8; i++){

       if (address[0] == '0'){

           tag = 0;

           firstBit = 0;

        } else if (address[0] == '1'){

           tag = 0;

           firstBit = 1;

        } else if (address[0] == '2'){

           tag =1;

           firstBit = 0;

        } else if (address[0] == '3'){

           tag = 1;

           firstBit = 1;

        } else if (address[0] == '4'){

           tag = 2;

           firstBit = 0;

        } else if (address[0] == '5'){

           tag = 2;

           firstBit = 1;

        }  else if (address[0] == '6'){

           tag = 3;

           firstBit = 0;

       } else if (address[0] == '7'){

           tag = 3;

           firstBit = 1;

       }  else if (address[0] == '8'){

           tag = 4;

           firstBit = 0;

       } else if (address[0] == '9'){

           tag = 4;

           firstBit = 1;

       }   else if (address[0] == 'A'){

           tag = 5;

           firstBit = 0;

       } else if (address[0] == 'B'){

           tag = 5;

           firstBit = 1;

       }  else if (address[0] == 'C'){

           tag = 6;

           firstBit = 0;

       } else if (address[0] == 'D'){

           tag = 6;

           firstBit = 1;

        }  else if (address[0] == 'E'){

           tag = 7;

           firstBit = 0;

       } else if (address[0] == 'F'){

           tag = 7;

           firstBit = 1;

       } else{

           cout<<"The Hex number is not valid"<< endl;

        }

   }

   if(address[1]>='0' && address[1]<'8'){

       secondBit = 0;

  }  else if(address[1]=='8'|| address[1]=='9'||(address[1]>='a' && address[1]<='f')){

       secondBit = 1;

   }  else{

       cout<<"The Hex number is not valid"<< endl;  

       return 0;

   }

   setNumber = firstBit * 2 + secondBit;

   if(cache[setNumber][0]==tag || cache[setNumber][1]==tag){

       cout<<"There is a hit";

   } else{

       cout<< "There is a miss";

   }

   return 0;

}

Explanation:

The C++ source code prompts the user for an input for the address variable, then the nested if statement is used to assign the value of the firstBit value given the value in the first index in the address character array. Another if statement is used to assign the value for the secondBit and then the setNumber is calculated.

If the setNumber is equal to the tag bit, Then the hit message is printed but a miss message is printed if not.

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2 years ago
Write a program that reads an integer, a list of words, and a character. The integer signifies how many words are in the list. T
MrMuchimi

In python 3.8:

user_input = input().split()

x = user_input[0]

char = user_input[-1]

for w in range(1,int(x)+1):

   if char in user_input[w]:

       print(user_input[w])

I hope this helps

7 0
3 years ago
Given positive integer numinsects, write a while loop that prints that number doubled without reaching 100. follow each number w
hichkok12 [17]
Hi,

the program is as follows
___________________________________________________________


import java.io.*;
class doubleval

  {
     public static void main()throws IOException   
     {

       DataInputStream dt=new DataInputStream(System.in); 

System.out.println("Enter NUMBER WHOSE DOUBLE U WANT TO                                           PRINT");       
            int n=Integer.parseInt(dt.readLine()); 

                  for(int i=n;i<=100;i=2*i)       
                    {           
                         System.out.println(i);       
                            }   
            }
}


           
3 0
2 years ago
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