Answer:
The output of the following code is "14".
Explanation:
In the python program firstly we define a function that is pass_it() function. In this function, we pass the two variable that is x,y. Then we define two variable z and result in the function. The z variable is used to store the multiplication value of the x,y. In the result variable, we use another function that is get_result() function in this function we pass the value of the z variable as a parameter. This function adds a value that is 2 and returns its value. Then we declare a variable that is num1 and num2. In this variable, we assign value that is 3 and 4 and return value of the pass_it() function in the answer variable and print it.
Answer: Port
Explanation :
When we port a software from one computer to another computer or from one operating system to another operating system, it tries to adapt to the new environment of the machine by checking the required the configurations of the machine and then checking the available files in the software to run the machine.
The porting of a software also checks whether the software is compatible with the machine or not and if not then why.
Answer:
a. 255.255.255.0 (class C)
b. 255.255.255.224
Explanation:
Here, we want to give the implied subnet mask of the given classful IPV4 address
We proceed as follows;
Given IPv4 address: 200.200.200.200
Classes
Class A : 0.0.0.0 to 127.255.255.255
Class B: 128.0.0.0 to 191.255.255.255
Class C: 192.0.0.0 to 223.255.255.255
Class D: 224.0.0.0 to 239.255.255.255
so 200.200.200.200 belongs to Class C and it's subnet mask is 255.255.255.0
In CIDR(Classless Inter Domain Routing)
subnet /27 bits means 27 1s and 5 0s. so subnet
i.e 11111111.11111111.11111111.11100000 which in dotted decimal format is 255.255.255.224 .
Answer:
a) Speedup gain is 1.428 times.
b) Speedup gain is 1.81 times.
Explanation:
in order to calculate the speedup again of an application that has a 60 percent parallel component using Anklahls Law is speedup which state that:
Where S is the portion of the application that must be performed serially, and N is the number of processing cores.
(a) For N = 2 processing cores, and a 60%, then S = 40% or 0.4
Thus, the speedup is:
Speedup gain is 1.428 times.
(b) For N = 4 processing cores and a 60%, then S = 40% or 0.4
Thus, the speedup is:
Speedup gain is 1.81 times.
